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ryzh [129]
2 years ago
9

B, C and D are points on a circle, centre O. AB and AD are tangents to the circle. Angle BCD=x Find an expression for the size o

f angle BAD in terms of x. Give your answer in its simplest form. Give reasons for each stage of your working.
Mathematics
1 answer:
stealth61 [152]2 years ago
3 0

Answer:

where the point B lie ,first say point B where lie

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Please help!! I need to get this done! Im begging you, brainliest and points!
Viefleur [7K]

Answer:

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

Step-by-step explanation:

See procedure below;

First let us make these two functions ( y = -x + 1 , y = x^2 + x - 2 ) equivalent;

- x + 1  = x^2 + x - 2,

-x - x + 1 + 2 - x^2 = 0,

- 2x + 3 - x^2 = 0,

x^2 + 2x - 3 = 0,

Now factor the simplified equation;

x^2 + 2x - 3 = 0,

( x^2 - x ) + ( 3x - 3 ) = 0,

x ( x - 1 ) + 3 ( x - 1 ) = 0,

( x - 1 )( x + 3 ) = 0,

And solve for x;

x - 1 = 0, and x + 3 = 0,

x = 1, and x = - 3

Now substitute this value of x into the two functions as to receive the y  values for each x - value;

y = - ( 1 ) + 1, <em>y = 0 for x = 1</em>,

y = ( - 3 )^2 - 3 - 2, y = 9 - 3 - 2, <em>y = 4 for x = - 3</em>,

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

8 0
1 year ago
What is the mixed number to 53/12
Virty [35]
The mixed number is 4 5/12.
6 0
2 years ago
Which is the graph of the system x + 3y &gt; –3 and y &lt; One-halfx + 1?
fenix001 [56]

Answer: THE GRAPH IS ATTACHED.

Step-by-step explanation:

We know that the lines are:

x + 3y=-3

y = \frac{1}{2} x + 1

Solving for "y" from the first line, we get:

3y=-x-3\\\\y=-\frac{x}{3}-1

In order to graph them, we can find the x-intercepts and the y-intercepts.

For the line x + 3y=-3 the x-intercepts is:

0=-\frac{x}{3}-1\\\\(1)(-3)=x\\\\x=-3

And the y-intercept is:

y=-\frac{0}{3}-1\\\\y=-1

For the line y=\frac{1}{2} x + 1 the x-intercepts is:

0=\frac{1}{2} x + 1\\\\-1(2)=x\\\\x=-2

And the y-intercept is:

y=\frac{1}{2} (0)+ 1\\\\y=1

 Now we can graph both lines, as you can observe in the image attached (The symbols and > indicates that the lines must be dashed).

By definition, the solution is the intersection region of all the solutions in the system of inequalities.

6 0
1 year ago
Read 2 more answers
How much heat is required to raise the temperature of
Elina [12.6K]

Answer:

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Step-by-step explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature = T_1 = 15°c

The final temperature = T_2  = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q =  m × s × ( T_2 - T_1 )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q =  50 g × 2260.0 J/g × 85°c

∴   Q = 9,605,000  joule

Or, Q =  9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer

4 0
1 year ago
Twenty-four 4-inch wide square posts are evenly spaced with 5 feet between adjacent posts to enclose a square field, as shown. W
Nata [24]

Answer:

492 0/10

Step-by-step explanation:

We have that the perimeter is 4 times the length of the side, now we know that this side "l" is given by:

l = 4 in * 24 + 23 * 5 ft

l = 96 in + 115 ft

Now, we pass the inches to pes, knowing that 1 foot equals 12 inches, so

96 in * 1 ft / 12 in = 8 ft

therefore replacing it remains:

l = 8 ft + 115 ft

l = 123 ft

now the perimeter:

p = 123 * 4

p = 492

to change to a mixed number:

4920/10 = 492 0/10

4 0
2 years ago
Read 2 more answers
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