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Eduardwww [97]
1 year ago
12

If x=3 is a solution of the equation 2x²-5x+k=0 find the value of k​

Mathematics
2 answers:
Novosadov [1.4K]1 year ago
8 0

Answer:

k = - 3

Step-by-step explanation:

Given that x = 3 is a solution then it satisfies the equation, that is

2(3)² - 5(3) + k = 0

2(9) - 15 + k = 0

18 - 15 + k = 0

3 + k = 0 ( subtract 3 from both sides )

k = - 3

ipn [44]1 year ago
5 0

Answer: k = -3

Step-by-step explanation:

2x²-5x+k=0

Substitute x=3

2(3)^2-5(3)+k=0

2(9)-15+k=0

18-15+k=0

3+k=0

k=-3

To check if your answer is correct you can substitute x=3 and k = -3

2(3)^2-5(3)-3=0

2(9)-15-3=0

18-15-3=0

3-3=0

So k = -3 is correct

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Answer:

standard deviation of these expected returns = 0.0295 or 2.95%

Step-by-step explanation:

The detailed step is shown in the attachment

8 0
1 year ago
The track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. Then they are able
klemol [59]
Answer: 15.7 minutes

Step-by-step explanation:

Let x be the time in the beginning (in minutes).

Given: The track team is trying to reduce their time for a relay race.

First they reduce their time by 2.1 minutes.

Then they are able to reduce that time by 10

If their final time is 3.96 minutes, then

x-t1-t2= 3.6
x= 3.6+ t1+ t2
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x= 15.7

Hence, their beginning time was 15.7 minutes.
3 0
1 year ago
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
1 year ago
Find the product of 0.094 ×0.367
Keith_Richards [23]
0.034498 is the answer
3 0
1 year ago
In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) =x2 to the number of x-intercepts in
Natalija [7]
Important:  Please use " ^ " to indicate exponentiation:

<span>"f(x) =x^2 to the number of x-intercepts in the graph of g(x) = x^2 +2."

Notes:  the graph of f(x) = x^2 is a vertical parabola that opens up.  It has its vertex at (0,0).  This is the only point at which f(x)=x^2 has a horiz. intercept.

g(x) = x^2 + 2 has a graph that looks the same as that of f(x) = x^2, EXCEPT that the whole graph is moved 2 units UP.  This new graph never touches or intersects the x-axis.  Therefore, g(x) has NO horiz. intercepts (no x-int.).

</span>
7 0
2 years ago
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