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Eduardwww [97]
1 year ago
12

If x=3 is a solution of the equation 2x²-5x+k=0 find the value of k​

Mathematics
2 answers:
Novosadov [1.4K]1 year ago
8 0

Answer:

k = - 3

Step-by-step explanation:

Given that x = 3 is a solution then it satisfies the equation, that is

2(3)² - 5(3) + k = 0

2(9) - 15 + k = 0

18 - 15 + k = 0

3 + k = 0 ( subtract 3 from both sides )

k = - 3

ipn [44]1 year ago
5 0

Answer: k = -3

Step-by-step explanation:

2x²-5x+k=0

Substitute x=3

2(3)^2-5(3)+k=0

2(9)-15+k=0

18-15+k=0

3+k=0

k=-3

To check if your answer is correct you can substitute x=3 and k = -3

2(3)^2-5(3)-3=0

2(9)-15-3=0

18-15-3=0

3-3=0

So k = -3 is correct

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You invested a total of $12,000 at 4.5 percent and 5 percent simple interest. During one year, the two accounts earned $570. How
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Answer: You invested $6000 in both accounts.

Step-by-step explanation:

Let x represent the amount invested in the account earning 4.5% interest.

Let y represent the amount invested in the account earning 5% interest.

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x + y = 12000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the account earning 4.5%

I = (x × 4.5 × 1)/100 = 0.045x

Considering the account earning 5%

I = (y × 5 × 1)/100 = 0.05y

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0.045x + 0.05y = 570 - - - - - - - - - - 1

Substituting x = 12000 - y into equation 1, it becomes

0.045(12000 - y) + 0.05y = 570

540 - 0.045y + 0.05y = 570

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0.005y = 30

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x = 12000 - y = 12000 - 6000

x = $6000

6 0
2 years ago
The growth of a species of fish in a lake can be modeled by the function ƒ(x) = 500(1.10)x, where x is time in months since Janu
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Answer:

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And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

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Where a is the constant or the initial amount, b te base and x the independnet variable (time)

For this special  case we know that:

a = 500, b =1.1

And 500 represent the constant or initial value for the function

Step-by-step explanation:

We have the following function given:

f(x) = 500(1.1)^x

And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

y= ab^x

Where a is the constant or the initial amount, b te base and x the independnet variable (time)

For this special  case we know that:

a = 500, b =1.1

And 500 represent the constant or initial value for the function

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2 years ago
Two weeks ago, Alice came home from vacation and noticed that a bean plant was growing in her garden. Today, the stalk is $452$
dimulka [17.4K]
So, on day 1, the plant was say "P" cm tall.

then 2 weeks go by, or 14 days, and the plant grew to 452 cm.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=P(1 + r)^t\qquad 
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A=\textit{accumulated amount}\to 452\\
P=\textit{initial amount}\\
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t=\textit{elapsed time}\to &14\\
\end{cases}
\\\\\\
452=P(1+0.05)^{14}\implies \cfrac{452}{1.05^{14}}=P
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