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Karolina [17]
2 years ago
15

Brent has a net spendable income of $1,600 per month. He needs to get a new car to drive to work. What car would best fit his bu

dget? A. Age/Type of Car: 7 years old, 4-door car Cost of monthly payments: $70 Expected fuel costs per month: $100 Average monthly maintenance costs: $200 B. Age/Type of Car: 3 years old, 2-door sports car Cost of monthly payments: $200 Expected fuel costs per month: $140 Average monthly maintenance costs: $30 C. Age/Type of Car: New, 4-door car Cost of monthly payments: $350 Expected fuel costs per month: $100 Average monthly maintenance costs: $20 D. Age/Type of Car: 6 years old, 4-door car Cost of monthly payments: $140 Expected fuel costs per month: $100 Average monthly maintenance costs: $50
Mathematics
1 answer:
Arlecino [84]2 years ago
7 0
The best and the most correct answer among the choices provided by the question is the fourth choice. The car that would best fit his budget is "<span> Age/Type of Car: 6 years old, 4-door car Cost of monthly payments: $140 Expected fuel costs per month: $100 Average monthly maintenance costs: $50" </span>I hope my answer has come to your help. God bless and have a nice day ahead!
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The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me
kkurt [141]

The final part of the question is asking;

How much did all (99.7%) of the students spend on textbooks in a semester

Answer:

almost all (99.7%) of the students spent between $165 and $315 on textbooks in a semester.

Step-by-step explanation:

The standard deviation rule describes to us that for distributions that have the normal shape, approximately 99.7% of the observations fall within 3 standard deviations of the mean.

In this question, we are given that; Mean = 240 and Standard deviation= 25

So, 3 standard deviation below the mean = Mean - 3(standard deviation)

= 240 - (3 × 25)

= 240 - 75 = 165

Now, 3 standard deviation above the mean = Mean + 3 standard deviation = 240 + (3 × 25)

= 240 + 75 = 315

So, almost all (99.7%) of the students spent between $165 and $315 on textbooks in a semester.

7 0
2 years ago
In circle O, what is m∠MAJ?
ira [324]

we know that

The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.

so

<u>Find the measure of the angle LAM</u>

m∠LAM is equal to

\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees

<u>Find the measure of the angle MAJ</u>

we know that

m∠LAM+m∠MAJ=180° ------> by supplementary angles

m∠MAJ=(180-125)

m∠MAJ=55°

therefore

<u>the answer is</u>

The measure of the angle MAJ is 55\ degrees

6 0
2 years ago
Read 2 more answers
Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

mean ( u ) = 8 ounces

std ( б )= 1.5

navel oranges = X

A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

                   = P ( Z > 2.33 ) = 0.0099

                   = 0.9%

B) percentage of oranges weighing less than 8.7 ounces

  P( x < 8.7 ) = P ( \frac{x - u}{ std} > \frac{8.7-8}{1.5} )

                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

7 0
2 years ago
A set of face cards contains 4 Jacks, 4 Queens, and 4 Kings. Carlie chooses a card from the set, records the type of card, and t
RUDIKE [14]
The correct answer to this question is that "<span>The experimental probability is 1/15 less than the theoretical probability."

The table as attached via image shows that the probability of getting a Jack is 2/5, getting a Queen is 4/15, and King is 1/3. That is the theoretical probability of each card to be drawn according to its frequency.
</span>
8 0
2 years ago
Read 2 more answers
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
2 years ago
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