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2 years ago

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The human eye blinks about 6.25x10 to the 6th power times each year. A seal blinks about 1.01x10 to the 3rd power times per year

. How many times do a human and a seal blink in one year?

1 answer:

OLEGan [10]2 years ago

8 0

A human blinks 6,250,000 times a year.
A seal blinks 1,010 times a year.

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your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the

solmaris [256]

Answer:

The answer is "$ 11,961.43"

Step-by-step explanation:

Given values:

P = $ 9500

r= 2.1 %

time (t)= 11 year

total quarterly year =4

Formula:

$A= P (1+\frac{r}{n})^{nt}\\\\$

quarterly time = $4 \times 11$

$= 44$

$A= P (1+\frac{r}{n})^{nt}\\\\$

$A = 9500 ( 1+ \frac{0.021}{4})^{44}\\\\A = 9500(\frac{4+ 0.021}{4} )^{44} \\\\A = 9500(\frac{4.021}{4} )^{44} \\\\A= 9500 (1.00525)^{44}\\\\A= 9500(1.25909819)\\\\A= 11,961. 43\\$

8 0

1 year ago

A bike and skate shop rents bikes for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make

omeli [17]

Ur answer is 6 (20+20+20+20+20+20+21+21+21+21+21+21+21+21+21+21+21+21=372) and they need at least 362 hope this helps I'm pretty sure this is right sorry if it's wrong but it seems right to me

8 0

2 years ago

Read 2 more answers

Using the extended Euclidean algorithm, find the multiplicative inverse of a. 135 mod 61 b. 7465 mod 2464 c. 42828 mod 6407

rodikova [14]

Answer:

(a)1≡47 mod 61

(b)1≡2329 mod 2464

(c)Does not exist

Step-by-step explanation:

The operation a(mod b) has an inverse if the the two integers (a,b)

are co-prime. i.e. their g.c.d is 1.

(a)Given 135 mod 61

We first reduce it to its lowest form.

135 mod 61=13 mod 61

61=13(4)+9 ==> 9=61-13(4)

13=9(1)+4 ==> 4=13-9(1)

9=4(2)+1 ==> 1=9-4(2)

4=1(4)

Next we rewrite 1 as a linear combination of 13 and 61.

1=9-4(2)

=9-(13-9(1))2

=9(3)-13(2)

=(61-13(4))(3)-13(2)

=61(3)-13(12)-13(2)

1=61(3)-13(14)

1=61(3)+13(-14)

1≡-14 mod 61≡(-14+61)mod 61

1≡47 mod 61

(b)7465 mod 2464

Reducing it to its lowest form

7465 mod 2464=73 mod 2464

2464=73(33)+55 ==>55=2464-73(33)

73= 55(1)+18 ==> 18=73-55(1)

55=18(3)+1 ==>1=55-18(3)

18=1(18)

Rewriting 1 as a linear combination of 73 and 2464.

1=55-18(3)

=2464-73(33)-(73-55(1))(3)

=2464-73(33)-73(3)+55(3)

=2464-73(36)+55(3)

=2464-73(36)+(2464-73(33))(3)

=2464-73(36)+2464(3)-73(99)

=2464(4)-73(135)

1=2464(4)+73(-135)

Therefore:

1≡-135 mod 2464

1≡(-135+2464)mod 2464

1≡2329 mod 2464

(c)42828 mod 6407

The two numbers are not co-prime. In fact their g.c.d is 43.

Therefore their inverse does not exist.

4 0

2 years ago

Read 2 more answers

(1 point) Let P(t) be the performance level of someone learning a skill as a function of the training time t. The derivative dPd

monitta

Answer:

$P(t)=M+Ce^{-kt}$

Step-by-step explanation:

Given the differential model

$\dfrac{dP}{dt}=k[M-P(t)]$

We are required to solve the equation for P(t).

$\dfrac{dP}{dt}=kM-kP(t)\\$Add kP(t) to both sides\\\dfrac{dP}{dt}+kP(t)=kM\\$Taking the integrating factor\\e^{\int k dt} =e^{kt}\\$Multiply all through by the integrating factor\\\dfrac{dP}{dt}e^{kt}+kP(t)e^{kt}=kMe^{kt}\\\dfrac{dP}{dt}e^{kt}=kMe^{kt}\\(Pe^{kt})'=kMe^{kt} dt\\$Take the integral of both sides with respect to t\\\int (Pe^{kt})'=\int kMe^{kt} dt\\Pe^{kt}=kM \int e^{kt} dt\\Pe^{kt}=\dfrac{kM}{k} e^{kt} + C_0, C_0$ a constant of integration$

$Pe^{kt}=Me^{kt} + C\\$Divide both side by e^{kt}\\P(t)=M+Ce^{-kt}\\P(t)=M+Ce^{-kt}\\$Therefore:\\P(t)=M+Ce^{-kt}$

4 0

1 year ago

Renee, Susan, and Martha will share the cost to rent a vacation house for a week. Renee will pay 40% of the cost. Susan will pa

notsponge [240]

Answer:

Martha is incorrect.

Amount paid by Renee = $\$340$

Amount paid by Susan = $297.5

Amount paid by Martha = $\$212.5$

Step-by-step explanation:

Given: Renee will pay 40% of the cost. Susan will pay 0.35 of the cost.Martha will pay the remainder of the cost. Martha thinks she will pay 13 of the cost.

To find: Is Martha correct?

To find: amount paid by each of Renee, Susan, and Martha

Solution:

Percentage of an amount paid by Renee = 40%

Percentage of an amount paid by Susan = 35%

So,

Percentage of an amount paid by Martha = $100-40-35=25\%$

But Martha thinks she will pay 13 of the cost. So, she is incorrect.

Amount paid by Renee = $\frac{40}{100}(850)=\$340$

Amount paid by Susan = $\frac{35}{100}(850)=\$297.5$

Amount paid by Martha = $\frac{25}{100}(850)=\$212.5$

5 0

1 year ago