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2 years ago

What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768

Mathematics

1 answer:

Pani-rosa [81]2 years ago

6 0

Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

Decimal form = 0.8

Fraction form = 4/5

Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

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<span>7x-6y=14
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Edited later:
</span>7x-6y=14
6x-y=-17
From second equation 6x - y = -17, we have y = 6x +17. Substitute this in the first equation to get
7x-6y=14
>> 7x-6(6x+17)=14
>> 7x-36x-102=14
>> 7x-36x=102+14
>> -29x=116
>> x=116/(-29)
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Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

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Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$

Therefore, Probability of atleast one of 12 student has food allergies

= $1-(\frac{93}{100})^{12}$

= $0.581403702521$

≈ 0.58 ( approx)

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