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sasho [114]
1 year ago
9

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics
1 answer:
Westkost [7]1 year ago
5 0

Answer:

3c

Step-by-step explanation:

average =  \frac{a + b + c}{3}

Substitute a= b +2c:

\frac{a + b + c}{3}  =  \frac{b + 2c + b + c}{3}  \\  \frac{a + b + c}{3}  =  \frac{2b + 3c}{3}

Substitute b= 3c:

\frac{a + b + c}{3}   = \frac{2(3c) + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{6c + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{9c}{3}  \\  \frac{a + b + c}{ 3}  = 3c

Thus, the average of the 3 numbers is 3c.

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X<br><img src="https://tex.z-dn.net/?f=x%200.8265%20%3D%2045%20" id="TexFormula1" title="x 0.8265 = 45 " alt="x 0.8265 = 45 " al
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