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2 years ago

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics

1 answer:

Westkost [7]2 years ago

5 0

Answer:

Step-by-step explanation:

$average = \frac{a + b + c}{3}$

Substitute a= b +2c:

$\frac{a + b + c}{3} = \frac{b + 2c + b + c}{3} \\ \frac{a + b + c}{3} = \frac{2b + 3c}{3}$

Substitute b= 3c:

$\frac{a + b + c}{3} = \frac{2(3c) + 3c}{3} \\ \frac{a + b + c}{3} = \frac{6c + 3c}{3} \\ \frac{a + b + c}{3} = \frac{9c}{3} \\ \frac{a + b + c}{ 3} = 3c$

Thus, the average of the 3 numbers is 3c.

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stich3 [128]

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Step-by-step explanation:

The blue line and the purple line are the lines corresponding to the equations of interest. Their point of intersection is in the 2nd quadrant, so is nearest to ...

(–1.4, 1.5)

It can be useful to understand that for equations in standard form:

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the x- and y-intercepts are ...

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2 years ago

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