Given: a=b+2c, b=3c. What is the average of numbers a, b and c?
1 answer:
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Answer:
D.The password must not follow order matter
Step-by-step explanation:
We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.
We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .
We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.
By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.
Permutation formula : The number of arrangements when taken r objects at a time out of n objects
=
Total letters in word NUMBER=N,U,M,B,E,R=6
n=6,r=4
Therefore, the number of arrangements can be made from 6 letters when 4 letters taken at a time =
The number of selection can be made from 6 letters when 4 letters taken at a time =
The number of selection can be made from 6 letters when 4 letters taken at a time =
The number of selection can be made from 6 letters when 4 letters taken at a time =360
Option D is correct.
Answer : D.The password must not follow order matter
Answer:
0.4
Step-by-step explanation:
Given:
Dana found that 8 students earned an A, 6 students earned a B, 4 students earned a C, and 2 students earned a D on the last science test.
To find:
the experimental probability that the student would have earned an A in the test
Solution:
Probability refers to the chances of occurrence of some event.
Number of students who earned an A in the test = 8
Total number of students = 8 + 6 + 4 + 2 = 20
The experimental probability that the student would have earned an A in the test = Number of students who earned an A in the test / Total number of students =