If AY parallel to CX, then find ∠ABCplease help!!!!!!!!!!!!!!!!!!!
1 answer:
Answer:
60°
Step-by-step explanation:
Through point B draw a line m || AY || CX and take two points say E and F on left and right side of point B respectively.
Therefore,
m∠FBC + m∠XCB = 180°..(By interior angle property)
m∠FBC + 130° = 180°
m∠FBC = 180° - 130°
m∠FBC = 50°....(1)
Next,
m∠ABF = m∠BAY... (Alternate angles)
m∠ABC + m∠FBC = 110°
(since, m∠ABF = m∠ABC + m∠FBC)
m∠ABC + 50° = 110° (From equation 1)
m∠ABC = 110° - 50°
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Answer:
100 in²
Step-by-step explanation:
The area of the banner is equal to the area of the initial rectangle minus the area of the cutout triangle.
The rectangle has a height of 8 inches and width of 14 inches, so its area is:
A = (8 in) (14 in) = 112 in²
The triangle has a base of 8 inches and a height of 3 inches, so its area is:
A = ½ (8 in) (3 in) = 12 in²
So the area of the banner is 112 in² − 12 in² = 100 in².
