Two distinct roots means two real solutions for x (the parabola needs to cross the x-axis twice)
Vertex form of a quadratic equation: (h,k) is vertex
y = a(x-h)^2 + k
The x of the vertex needs to equal 3
y = a(x-3)^2 + k
In order to have two distinct roots the parabola must be (+a) upward facing with vertex below the x-axis or (-a) downward facing with vertex above the x-axis. Parabolas are symmetrical so for an easy factorable equation make "a" 1 or -1 depending on if you want the upward/downward facing one.
y = (x-3)^2 - 1
Vertex (3,-1) upwards facing with two distinct roots 4 and 2
y = x^2 -6x + 9 - 1
y = x^2 -6x + 8
y = (x - 4)(x - 2)
Answer:
No, it would have to have been greater than .192 to invalidate the claim.
Step-by-step explanation:
Step-by-step explanation:
Given the equation that represents this order expressed as;
The number of tiles = 12b + 38 where;
b is the the number of bundles ordered
If a customer needs 150 tiles, the total number of bundles ordered can be gotten by simply substituting The number of tiles into the modeled equation and find the value of b. This is as shown below;
On substituting;
150 = 12b + 38
12b = 150 - 38
12b = 112
b = 112/12
b = 9.33
b ≈ 9 bundles
We need to round up the problem because the number of tiles can not be in fraction but as whole numbers.
