Answer:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation

And replacing we got:

So then the sample proportion of bare ground spots is 0.792 for this sample
Step-by-step explanation:
We have the following info given from the problem:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation)
And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

And replacing we got:

So then the sample proportion of bare ground spots is 0.792 for this sample
At first, I thought this was going to be a dog of a bear of a problem,
but then I fixated it with my steely burning gaze and it fell apart for me.
The volume of a pyramid is (1/3) (base area) (height)
Each of these pyramids has the same base area and the
same height, so ...
Volume of the lower pyramid = (1/3) (base area) (height)
Volume of the upper pyramid = (1/3) (base area) (height)
Combined volume of both pyramids = (2/3) (base area) (height) .
Now, how do the pyramids relate to the rectangular prism ?
Their base area is (length x width) of the prism, and
their height is (1/2 the height) of the prism.
From here, we'll work with the dimensions of the prism ... L, W, and H .
Combined volume of the pyramids = (2/3) (L x W) (1/2 H)
= (1/3) (L x W x H) .
Volume of the prism = (L x W x H)
The pyramids occupy 1/3 the volume of the prism.
The ratio is 1/3 .
Answer:
Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.
Question 14: The club was making a loss between 11.28 and 4.88 years.
Step-by-step explanation:
Question 13:
The age group y for which the response rate R is 8 microseconds is given by the solution of the equation

We graph this equation and find the solutions to be

Since only positive solutions for y are valid in the real world we take only those.
Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.
Question 14:
The footbal club is making a loss when 
Or

We graph this inequality and find the solutions to be
and 
Since in the real world only positive values for t are valid, we take the the second solution to be true.
Thus the club was making a loss in years 
1/10 is the same as saying 10 times less
Refer to the diagram below
The digit as the first decimal place is worth 1/10
The digit as the second decimal place is worth 1/100 which is 1/10 worth the digit as the first decimal place
Example of two decimal numbers:
2.56 and 2.68
The digit 6 in 2.56 is 6/100
The digit 6 in 2.68 is 6/10
The digit 6 in 2.56 is 1/10 as much as the digit 6 in 2.68