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Marina CMI [18]

2 years ago

13

In 2011, the average daily temperature in Darrtown was 65°F. In 2012, the average daily temperature increased by 3% but then dec

reased by 4.5% in 2013.
What was the daily average temperature in Darrtown in 2013?
A. 62°F
B. 64°F
C. 68°F
D. 74°F

2 answers:

Liono4ka [1.6K]2 years ago

6 0

Not very sure but it might be C

marta [7]2 years ago

3 0

Answer:

c

Step-by-step explanation:

because 65+3%+4.5=69

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The Fibonacci sequence was first discovered during a study of rabbits. If newborn rabbits become adults in one month, each pair

Rina8888 [55]

Answer:

There will be 233 pairs of rabbits would be produced after thirteen months.

Step-by-step explanation:

Consider the provided information.

In the Fibonacci sequence we can find the next term by adding the two numbers before it.

Let us consider that we have 1 pair of newborn rabbits in first month.

Then in the second month they will fully grow.

On the next month 1 more pair of baby rabbits were born.

Next month the baby rabbits were grown and the first pair had two more baby rabbits.

Thus the sequence will look like:

Sequence: 1, 1, 2, 3

It is given that the it follows the Fibonacci sequence. Now use the above rule to generate the Fibonacci sequence.

The required Sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233...

We need to find the number of pairs of rabbits would be produced after thirteen months.

Now from the above sequence we can find the number of rabbits produced after thirteen months.

Hence, there will be 233 pairs of rabbits would be produced after thirteen months.

4 0

2 years ago

In a basketball tournament, team A scored 6 more points than 3 times as many points as team B scored. Team C scored 45 more poin

Sophie [7]

A + B + C = 476
A = 3B + 6
C = B + 45

now its just a matter of subbing..
A + B + C = 476
(3B + 6) + B + (B + 45) = 476...combine like terms
5B + 51 = 476
5B = 476 - 51
5B = 425
B = 425/5
B = 85 <== team B scored 85

A = 3B + 6
A = 3(85) + 6
A = 255 + 6
A = 261 <=== team A scored 261

C = B + 45
C = 85 + 45
C = 130 <=== team C scored 130

6 0

2 years ago

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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.

BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to $160\ ft^{2}$

Part b) The volume is equal to $240\ ft^{3}$

Part c) The volume water left in the trough will be $84\ ft^{3}$

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

$A=2[12*5]=120\ ft^{2}$

<em>Find the area of two trapezoids</em>

$A=2[\frac{1}{2}(8+2)h]$

Applying Pythagoras theorem calculate the height h

$h^{2}=5^{2}-3^{2}$

$h^{2}=16$

$h=4\ ft$

substitute the value of h to find the area

$A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}$

The exterior surface area is equal to

$120\ ft^{2}+40\ ft^{2}=160\ ft^{2}$

Part b) Find the volume

We know that

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=20\ ft^{2}$

$L=12\ ft$

substitute

$V=20(12)=240\ ft^{3}$

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

$A=\frac{1}{2}(5+2)(2)=7\ ft^{2}$

<em>step 2</em>

Find the volume

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=7\ ft^{2}$

$L=12\ ft$

substitute

$V=7(12)=84\ ft^{3}$

4 0

2 years ago

The curvature of the Tacoma Narrows Bridge in

8_murik_8 [283]

Answer:

Width of the arch = 105 m

Step-by-step explanation:

Function representing the width of the arch,

f(x) = -0.016(x - 52.5)² + 45

where x = width of the base of the arch or horizontal distance from arch's left end

f(x) = vertical distance of the arch

From the given quadratic function, vertex of the parabola is (52.5, 45).

Coordinates of the vertex represents,

Height of the arch = 45 m

Half of the horizontal distance from the left end = 52.5 m

Therefore, width of the bridge = 2(Half the width of the bridge from left end) = 2×52.5

= 105 m

Therefore, given bridge is 105 m wide.

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2 years ago

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4\25 is the proportion of the percentage

5 0

2 years ago

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