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vovangra [49]
1 year ago
7

(03.02 HC)Amy, Dan, and Mike are competing in a cooking competition. They all used different amounts of milk from a container ho

lding 6 gallons of milk. Amy used 13% of the total milk in the container. Dan used 0.14 of the total milk in the container. Mike used 0.5 gallon of the total milk in the container. Who used the greatest amount of milk from the container? Show your work and explain your answer in words.
Mathematics
2 answers:
jok3333 [9.3K]1 year ago
8 0
Mike used 1/2 gallon which is .5 of a gallon
Amy used 13% of 6 gallons which is .13 * 6 = .78 of a gallon
Dan used 14% of 6 gallons which is .14 * 6 = .84 of a gallon

Dan used the most amount of milk.
ivolga24 [154]1 year ago
4 0
Mike used the most milk because .5 is 50%  which is 3 gallons out of the container dan used 14% of the milk and amy used 13% which means amy used the least and mike used the most.

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Suppose that we wish to expand (x + y + z)17. what is the coefficient of x 2 y5z10
Delvig [45]
We use the trinomial theorem to answer this question. Suppose we have a trinomial (a + b + c)ⁿ, we can determine any term to be:

[n!/(n-m)!(m-k)!k!] a^(n-m) b^(m-k) c^k

In this problem, the variables are: x=a, y=b and z=c. We already know the exponents of the variables. So, we equate this with the form of the trinomial theorem.

n - m = 2
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m - 10 = 5
m = 15

n - 15 = 2
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6 0
2 years ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
AT&T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

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To find:

The inequality for the given situation.

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It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

8 0
1 year ago
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