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2 years ago

Olivia counted the number of ladybugs on each plant in her garden, then made the graph below.

Mathematics

1 answer:

Leni [432]2 years ago

5 0

Answer:

A) Roses , C) Alfalfa

Step-by-step explanation:

Each ladybug symbol = 5 ladybugs

Roses: 35 ladybugs

Lettuce: 15 ladybugs

Alfalfa: 25 ladybugs

Grape vines: 10 ladybugs

10 ladybugs go from lettuce to alfalfa. You end up with:

Roses: 35 ladybugs

Lettuce: 5 ladybugs

Alfalfa: 35 ladybugs

Grape vines: 10 ladybugs

Roses and alfalfa end up with 35 ladybugs each.

Answer: A) Roses , C) Alfalfa

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Amanda and Alexis live 4 miles apart. They decide to start walking toward each other’s houses at the same time. Amanda walks at

pishuonlain [190]

Answer:

t = 0.53 hr

Step-by-step explanation:

We write expressions for the distances walked by these two people, sum them up and set the sum equal to 4 miles:

(3.5 mph)(t) + (4mph)(t) = 4 mi

Combining these terms:

(7.5 mph)(t) = 4 mi

4 mi

Solving for t: t = ---------------- = 0.53 hr

7.5 mph

5 0

1 year ago

Simplify the expression <br> (7v^2 )(10u^3v^5)(8uv^3)

Marizza181 [45]

Answer:

$560v^{10}u^{4}$

Step-by-step explanation:

Simplify the expression.

8 0

2 years ago

Explain how knowing 1+7 helps you find the sum for7+1

ss7ja [257]

1+7 and 7+1 are the same equations. The numbers are just switched around .
Example:
1+2=3
2+1+3

<span>They add up to the same answer no matter where they are placed, therefore knowing 1+7 helps you find the sum of 7+1 (again, because they are the same) </span>

8 0

2 years ago

Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$

Therefore, Probability of atleast one of 12 student has food allergies

= $1-(\frac{93}{100})^{12}$

= $0.581403702521$

≈ 0.58 ( approx)

8 0

2 years ago

Read 2 more answers

Vocabulary quiz scores for the 20 students in Mr. Harley’s class are shown in the table. Use this data to answer questions 4 and

CaHeK987 [17]

Answer:

The mean should be 80.5. This means the average number of test scores is 80.5. The mean absolute deviation should be 15.5. This means the average of the values are less than the mean by about 15.5.

4 0

2 years ago