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1 year ago

Olivia counted the number of ladybugs on each plant in her garden, then made the graph below.

Mathematics

1 answer:

Leni [432]1 year ago

5 0

Answer:

A) Roses , C) Alfalfa

Step-by-step explanation:

Each ladybug symbol = 5 ladybugs

Roses: 35 ladybugs

Lettuce: 15 ladybugs

Alfalfa: 25 ladybugs

Grape vines: 10 ladybugs

10 ladybugs go from lettuce to alfalfa. You end up with:

Roses: 35 ladybugs

Lettuce: 5 ladybugs

Alfalfa: 35 ladybugs

Grape vines: 10 ladybugs

Roses and alfalfa end up with 35 ladybugs each.

Answer: A) Roses , C) Alfalfa

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PLEASE HELP THANK YOUUUU Your group has $120 available for the banquet. Any other costs must be covered from selling tickets for

Keith_Richards [23]

Answer:

The cost C, of hosting the banquet with the services of Caterer One is;

C = $ 45·n

The cost C, of hosting the banquet with the services of Caterer Two is;

C = $250 + $ 28·n

The cost C, of hosting the banquet with the services of Caterer Three is;

C = $500 + $ 20·n

Step-by-step explanation:

The information includes;

The amount available to the group for the banquet = $120

The number of people attending the banquet = n

The cost incurred in hosting the banquet = C

The major costs in hosting the banquet are hall rental and caterer

The cost per caterer are as follows;

Caterer One

The cost per person including the hall = $45

Therefore, the cost incurred, C, in hosting the banquet using caterer one is equal;

C = n × $45 = $ 45·n

Caterer Two

The hall rental = $250

The cost per person = $28

Therefore, the cost incurred, C, in hosting the banquet using caterer two is equal;

C = $250 + n × $28 = $250 + $ 28·n

Caterer Three

The hall rental = $500

The cost per person = $20

Therefore, the cost incurred, C, in hosting the banquet using caterer three is equal;

C = $500 + n × $20 = $500 + $ 20·n.

5 0

1 year ago

1. Lisa and Tomas Lopez are buying a new minivan that has a base

Dimas [21]

The question is incomplete:

Lisa and Tomas Lopez are buying a new minivan that has a base price of $22,510.the options total $8,062 and destination charge is $770. The dealer's cost is estimated to be 91% of the base price and 88% of the options.

-What is the sticker price of the vehicle?

-Find the dealer's percent of the base price.

-Find the dealer's percent of the options price.

-What is the estimated dealer's cost?

Answer:

-What is the sticker price of the vehicle? $31,342

-Find the dealer's percent of the base price: $20,484

-Find the dealer's percent of the options price: $7,094

-What is the estimated dealer's cost? $28,348

Step-by-step explanation:

-The sticker price is the result of adding the base price plus the options plus the destination charge.

Sticker price= base price + options + destination charge

Sticker price= $22,510+$8,062+$770

Sticker price= $31,342

-Dealer's percent of the base price: It is 91% of the base price:

$22,510*91%= $20,484

-Dealer's percent of the options price: It is 88% of the options:

$8,062*88%= $7,094

-Estimated dealer's cost= Percent of base price+percent of options price+destination charge

Estimated dealer's cost= $20,484+$7,094+$770

Estimated dealer's cost=$28,348

4 0

2 years ago

Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is

FinnZ [79.3K]

The vector product of $\boxed{a \times b = - 43\hat k}$ and the magnitude of $a \times b$ is $\boxed{43}.$

Further explanation:

Given:

Vector a is $\vec a = 4.00\hat i + 7.00\hat j.$

Vector b is $\vec b = 5.00\hat i - 2.00\hat j.$

Explanation:

The cross product of a \times b can be obtained as follows,

$\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}$

The vector can be expressed as follows,

$a \times b = - 43\hat k$

The magnitude of $a \times b$ can be obtained as follows,

$\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}$ 43404

The vector product of $\boxed{a \times b = - 43\hat k}$ and the magnitude of $a \times b$ is $\boxed{43}.$

Learn more:

Learn more about inverse of the functionhttps://brainly.com/question/1632445.
Learn more about equation of circle brainly.com/question/1506955.
Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

8 0

1 year ago

Read 2 more answers

Monique made several batches of soup for a potluck supper. Each batch required Three-fourths of a pound of potatoes, and she use

mr Goodwill [35]

Answer:

its 8 2/3

Step-by-step explanation: I got it right on edg

4 0

2 years ago

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Osvoldo has a goal of getting at least 30\%30%30, percent of his grams of carbohydrates each day from whole grains. Today, he at

Alchen [17]

Hi there! Osvoldo did not meet his goal.

(In my answering I suppose you mean 30%, 220 grams of carbohydrates and 55 grams of whole grains, if this is incorrect, please let me know)

Today Osvoldo ate 220 grams of carbohydrates.
10 % of 220 is 22 (divide by 10), and therefore 30 % of 220 is 22 * 3 = 66.

If at least 66 grams of Osvoldo's total consumption consisted of whole grains, he would have met his goal. However, he only ate 55 grams of whole grains (which is less than 66), and therefore he did not meet his goal.

8 0

1 year ago

Read 2 more answers