1. Count 12% of 532,475:
532,475 - 100%
x - 12%
Use proportion to find x:
This means that 63,897 electric guitars were sold with full-replacement warranty and 532,475-63,897=468,578 electric guitars were sold without full-replacement warranty.
2. If the manufacturer sells 468,578 electric guitars without full-replacement warranty, then he gain profit
$225·468,578=$105,430,050
from the warranties.
Answer: $105,430,050
Answer:
(B)93
Explanation:
Since we are using a fixed-order-interval model,
The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand
Where:
d=weekly demand
OI=Order Interval
LT=Lead Time
z=Standard Deviation of Desired Service Level
=Standard Deviation of weekly Demand
A= Amount at Hand
Answer:
The standard error of the proportion is 0.0367.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the standard error is
In this question:
So
The standard error of the proportion is 0.0367.
Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
