890×(1+0.187÷12)^(12)−890×(1+0.125÷12)^(12)=63.61....answer
Answer:
Hope this helps
Step-by-step explanation:
If 6 planters= $18 then 16 planters= 16x 18 divided by 6 =$48
Answer:
There were 6 onion rings and 2 slider in the combination meal.
Step-by-step explanation:
Let x be the number of onion rings and y be the number of slider.
Calories in one onion ring = 45 calories
Calories in one slider = 325 calories
Total number of calories = 920
Thus, we can write the equation:

There are 3 times as many onion rings as the sliders.
Thus, we can write the equation:

Solving the two equation by substitution method, we get,

Thus, there were 6 onion rings and 2 slider in the combination meal.
The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t
Answer
Given,
Mass of the Uranus, M = 8.68 x 10²⁵ Kg
Radius of Uranus, R = 2.56 x 10⁷ m
Distance of Uranus, D = 2.87 x 10¹² days
a) Rotational Kinetic energy of the Uranus
moment of inertia of the Uranus
I = 22.75 x 10³⁹ kg.m²
Angular speed
\

Rotational Kinetic energy



b) Rotational Kinetic energy of Uranus in its orbit around sun
moment of inertia of the Uranus
I = 7.15 x 10⁵⁰ kg.m²
Angular speed
\

Rotational Kinetic energy


