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aleksklad [387]
2 years ago
6

14. What is the next letter? B A D E H G J K a.L b.M c.N d.O

Mathematics
2 answers:
kolbaska11 [484]2 years ago
6 0

The pattern is 2 letters reverse order ( AB is written as BA).

Then it skips a letter ( there is no C)

Then the next two letters are in correct order ( DE)

Then it skips a letter ( no F)

Then it reverses order for the next two ( GH is written as HG)

Skip a letter ( no I)

Next two are correct order ( JK)


Then it would skip another letter ( so no L)

Then the next letters would be in order, so the next letter would be M.


The answer is b. M

topjm [15]2 years ago
5 0

Answer:

N

Step-by-step explanation:

Convert the letters to numbers,


it goes even, odd alternating and skipping ..

B A D E H G J K

in numbers, that is;

2 ,1,4,5,8,7,10,11

So the even sequence is: 2,4,8,10...

and the odd sequence is: 1,5,7,11,...

Next is an even number, since we see that the numbers 3, 6 and 9 are not included the sequence is skipping multiples of 3.. therefore the next even number after 10 might be 12, but since 12 is a multiple of 3, we skip that and choose 14. The 14th letter in the alphabet is N.

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Answer:

The answer is "Screen B is wider , because 5.3 is greater than 5 and one-third".

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The mobile display unit must be made similar. Phone A uses a decimal device, and telephone B uses a fraction in this case.

It's easier for you to use. Attempt using the decimal. The width of the phone B fraction could then be translated to decimal width. The computing is:

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<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

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4 0
2 years ago
In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev
tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

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99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

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The standard deviation of that data set is 3.8

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Let's say we have 12 chickens.

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OOOOC (Woah, that chicken is split in half!)

What fraction is 4.5 of the original amount?

Well, that's for you to find out! Good luck in solving this question.
3 0
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