So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.
So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>
Our result:
![\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Cbf%7B2a%5E2b%20%5Csqrt%5B4%5D%7B24a%5E2b%5E3%7D%20%7D%7D%7D)
We didn't just multiplied it, we also simplified it also.
Let's solve for d.
fd=(7)(1.06)d
Step 1: Add -7.42d to both sides.
df+−7.42d=7.42d+−7.42d
df−7.42d=0
Step 2: Factor out variable d.
d(f−7.42)=0
Step 3: Divide both sides by f-7.42.
d(f−7.42)f−7.42=0f−7.42
d=0f−7.42
Answer:
d=0f−7.42
PLEASE MARK ME AS BRAINLIEST
Wei la dooblave hexagono 8 solutes x n o solutes = questionnairre
we will find number of non-zero elements on each rows
and then we add them
First row:
we can see that non-zero elements are
2 , 3.1 , 22 , 9
so, number of non-zero elements in first row =4
Second row:
we can see that non-zero elements are
21 , 3.2 , 6
so, number of non-zero elements in first row =3
Third row:
we can see that non-zero elements are
1 , 42 , 8
so, number of non-zero elements in first row =3
Fourth row:
we can see that non-zero elements are
40 ,4 , 6,14
so, number of non-zero elements in first row =4
Fifth row:
we can see that non-zero elements are
10 , 20 , 13 , 5 , 6.3
so, number of non-zero elements in first row =5
now, we can add them
so,
total number of non-zero elements = 4 +3+3+4+5
so,
total number of non-zero elements is 19...........Answer
Answer:
Change = -(1/2) * 30 = -15 inches
Step-by-step explanation:
If the water level decreases by 1/2 inch each day, the change in the water level in one day is -1/2 inch.
So, after t days, the total change in the water level can be calculated as:
Total change = -(1/2) * t inches
So, after 30 summer days, the total change is:
Change = -(1/2) * 30 = -15 inches
So the water level of the pool after 30 summer days has decreased by 15 inches.
