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Rzqust [24]
2 years ago
11

THEIR AGES

Mathematics
1 answer:
snow_tiger [21]2 years ago
6 0

Answer:

Tom’s age is 7 years

Mary’s age is 13 years

Step-by-step explanation:

Since we do not know the ages, let’s represent the ages by variables at first.

Let m represent mary’s age will t represent Tom’s age.

Now, let’s proceed to have equations.

Adding square of Tom’s age (t^2) to mary’s age give 62

t^2 + m = 62 •••••••(i)

Adding square of mary’s age (m^2) to Tom’s age give 176

m^2 + t = 176 •••••••(ii)

Now, to get the individual ages, we will need to solve both equations simultaneously.

Solving both equations simultaneously without mathematical softwares can be a little hard.

By the use of mathematical software ( wolfram alpha to be specific), we can input both equations and allow the software to solve.

By inputing these equations, we have the values of t to be 7 and m to be 13

And if we try to check by inspection, we can see that these values are actually correct.

7^2 + 13 = 62

13^2 + 7 = 176

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At a desert resort, the temperature at 7 a.m. was 3°C. The temperature increased by an average of 3.4°C each hour until it reach
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Answer: It will take 8 hours to reach this temperature.

Step-by-step explanation:

Given: At a desert resort, the temperature at 7 a.m. was 3°C.

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Let x be the number of hours taken to reach 30.2°C..

As per given ,

Initial temperature +(average increase in temperature) (Number of hours) = 30.2

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If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a
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Answer:

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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T
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Step-by-step explanation:

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So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. In this problem, \sigma = 0.25

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

M = z*\frac{\sigma}{\sqrt{n}}

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0.1\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.1}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

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(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

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0.06\sqrt{n} = 1.96*0.25

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