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1 year ago

Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)

Mathematics

2 answers:

nikitadnepr [17]1 year ago

7 0

8x+4y+(-8z^2)+[3z+(-5z)] the answer is D

Softa [21]1 year ago

3 0

we are given

$(8x+3z-8z^2)+(4y-5z)$

we can group x-terms with x and y-terms with y and z terms with z

so, we get

$=8x+3z-8z^2+4y-5z$

we can make groups

$=8x+4y+3z-8z^2-5z$

$=8x+4y+3z-5z-8z^2$

we can also write it as

$=8x+4y+(-8z^2)+[3z+(-5z)]$

so, option-D.........Answer

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2 years ago

A town has a population of 14,000 and grows 5% every year. What will be the population after 14 years, to the nearest whole numb

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Step-by-step explanation:

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2 years ago

What is 4973 divided by 7

Firlakuza [10]

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2 years ago

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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

lesya [120]

Answer:

a) the sample size (n) = 156.25≅ 156

Step-by-step explanation:

Step1 :-

Given the two sample sizes are equal so $n_{1} =n_{2} = n$

Given the standard error (S.E) = 0.04

The standard error of the proportion of the given sample size

$S.E = \sqrt{\frac{pq}{n} }$

Step 2:-

here we assume that the proportion of boys and girls are equally likely

p= 1/2 and q= 1/2

$S.E = \sqrt{\frac{p(1-p)}{n} } \leq \frac{\frac{1}{2} }{\sqrt{n} }$

$\sqrt{n} = \frac{\frac{1}{2} }{S.E}$

squaring on both sides, we get

$n = \frac{1}{(2X0.04)^{2} }$

on simplification, we get

n= 156.25 ≅ 156

sample size (n) = 156

verification:-

$S.E = \sqrt{\frac{pq}{n} }= \sqrt{\frac{1}{4X156} } =\sqrt{0.0016}$

Standard error = 0.04

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1 year ago

The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.

DochEvi [55]

Answer:

There are two rational roots for f(x)

Step-by-step explanation:

We are given a function

$f(x) = x^6-2x^4-5x^2+6$

To find the number of rational roots for f(x).

Let us use remainder theorem that when

f(a) =0, (x-a) is a factor of f(x) or x=a is one solution.

Substitute 1 for x

f(1) = 1-2-5+6=0

Hence x=1 is one solution.

Let us try x=-1

f(-1) = 1-2-5+6 =0

So x =-1 is also a solution and x+1 is a factor

We can write f(x) by trial and error as

$f(x) = (x-1)(x+1)(x^2-3)$

We find that $f(x) (x^2-3)$ factor gives two irrational solutions as

±√3.

Hence number of rational roots are 2.

5 0

1 year ago

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