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2 years ago

Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)

Mathematics

2 answers:

nikitadnepr [17]2 years ago

7 0

8x+4y+(-8z^2)+[3z+(-5z)] the answer is D

Softa [21]2 years ago

3 0

we are given

$(8x+3z-8z^2)+(4y-5z)$

we can group x-terms with x and y-terms with y and z terms with z

so, we get

$=8x+3z-8z^2+4y-5z$

we can make groups

$=8x+4y+3z-8z^2-5z$

$=8x+4y+3z-5z-8z^2$

we can also write it as

$=8x+4y+(-8z^2)+[3z+(-5z)]$

so, option-D.........Answer

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The subjects of a study by Dugoff et al. (A-5) were 10 obstetrics and gynecology interns at the University of Colorado Health Sc

astra-53 [7]

Answer:

The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).

Step-by-step explanation:

Intern No. of Breast

Number Exams Performed X²

1 30 900

2 40 1600

3 8 64

4 20 400

5 26 676

6 35 1225

7 35 1225

8 20 400

9 25 625

10 20 400

 ∑ 259 ∑ 7515

Mean= X`= ∑x/n= 259/10= 25.9

Variance = s²= 1/n-1[∑X²- (∑x)²/n]

= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]

= 806.9/9=89.655= 89.66

Standard Deviation= √89.655= 9.4687

Hence

The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262

The 95 % Confidence interval is given by

x`±t(∝,n-1) s/√n

So Putting the values

25.9± 2.262( 9.4687/√10)

= 25.9 ±2.262 (2.9943)

= 25.9 ± 6.7730

= 25.9 +6.7730=32.6730

25.9 -6.7730= 19.1269

= 19.1269, 32.6730

The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).

6 0

2 years ago

A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way t

Alekssandra [29.7K]

Answer:

H(t) = 15 -6sin(2.5π(t -0.5))

Step-by-step explanation:

For midline M, amplitude A, period T and time t0 at which the function is decreasing from the midline, the function can be written as ...

H(t) = M -Asin(2π/T(t -t0))

Using the given values of M=15, A=6, T=0.8 and t0 = 0.5, the equation is ...

H(t) = 15 -6sin(2.5π(t -0.5))

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2 years ago

HJ is twice JK. J is between H and K. If HJ= 4x and HK=78, find Jk.

ss7ja [257]

You'll find it easier to understand if you illustrate the problem as what is shown in the attached picture. From the illustration and the problem description, two equations can be formulated:

HJ = 2JK
HJ + JK = HK

2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26

6 0

2 years ago

In triangle $DEF,$ $\angle D = 30^\circ,$ $\angle F = 60^\circ,$ and $EF = 6.$ Find $DE + DF.$ [asy] unitsize(2 cm); pair D, E,

sergey [27]

Answer:

Step-by-step explanation:

The answer to this question is 12+6sqrt3.

This is because of the 30, 60, and 90 degree rule. The rule states that the hypotenuse is equal to twice the length of the shorter leg, which is the side across from the 30 degree angle.

Using the rule you now know that DF is 12. Then use the Pythagorean Theorem to find the length of DE. 12^2=144, and 6^2=36. 144-36=108.

The square root of 108 simplified=6sqrt3.

Then you add them together and get 12+6sqrt3.

5 0

2 years ago

Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,

Readme [11.4K]

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

Therefore the value of the equation is:

6 0

2 years ago

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