Answer:
The answer is 390 × pi.
Step-by-step explanation:
Big cone:
V = 1/3 x pi x r^2 x h
= 1/3 x 3.14 x 9^2 x 15
= 1272.3 cubic inches
Small cone:
V = 1/3 x pi x r^2 x h
= 1/3 x 3.14 x 3^2 x 5
= 47.1 cubic inches
1272.3 - 47.1 = 1225.2 cubic inches
1272/3.14 ≈ 390
The answer is 390 × pi.
There is multiple ways but one of them is 3 SUV and 1 car and that will give him $315.
I hope this helps :)
The y-intercept of the graph of a function is the value of f(0) for any function f.
That is, it is the y-value in the pair (0, y)
The y-intercept of <span>f(x) = 4x + 5 is f(0)=4*0+5=5
The y-intercept of (0, 2) is 2.
The y-intercept of </span>h(x) = 3 sin(2x + π) − 2 is:
h(0) = 3 sin(2*0 + π) − 2=3 sin(π) − 2=3*0-2=-2
<span>Answer: The function f has the greatest y-intercept.
</span>
For this case we can make the following rule of three:
2/9 ------> 3/5
x ---------> 1
Clearing x we have:
x = (1 / (3/5)) * (2/9)
Rewriting we have:
x = (5/3) * (2/9)
x = 10/27
Answer:
he irons 10/27 of his shirt every minute
The answer is 1 gallon.
Miles per gallon(mpg) is computed by dividing the distance traveled by the how many gallons used. So you can derive a formula for how many gallons you would use given the mpg. You will end up with:

The problem asks for how many gallons of gas she will safe in a five-day work work week. So first you need to compute how many miles that would be.
54 miles/day x 5days =
270 milesSo in a five day work week, she will travel 270 miles.
Now to see how much gas she will save, compute how many gallons she will use up for each car, given the mpg of each and find the difference.
First model:30 mpg

This means that with the first model, she will have used up
9 gallons in a 5-day work week.
Second model: 27 mpg


This means that with the second model, she will have used up 10g in a 5-day work week.
Now for the last bit. How much will she save? You can get that by getting the difference of how many gallons each car would have used up.
10gallons - 9gallons = 1gSo she would have saved
1 gallon of gas if she buys the first car instead of the second.