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GrogVix [38]
1 year ago
6

A study was conducted on the effects of long-term marriage (more than 10 years). Researchers gathered data from a random sample

of 4,563 adults and measured quite a few variables, in addition to the explanatory variable of marriage and the response variable of longer life span. According to a newspaper article summarizing the study, those in long-term marriages were more likely to be more physically active, at a healthy weight, and nonsmokers. Those who were not married were about 20% more likely to be deceased. What conclusion can we draw from this study? Explain.
We can infer a cause-and-effect relationship because the sample was selected randomly.

We cannot infer a cause-and-effect relationship because treatments were not assigned randomly.

We cannot infer a cause-and-effect relationship because we do not have a control group.

We can infer a cause-and-effect relationship because multiple variables were included.

We cannot infer a cause-and-effect relationship because the treatments imposed were not blocked correctly.
Mathematics
1 answer:
True [87]1 year ago
8 0

Answer:

The correct option is;

We cannot infer a cause and effect relationship because the multiple variables were included

Step-by-step explanation:

The criteria required in order to establish a cause and effect relationship includes the following;

1) There must be a temporal precedence between the cause and the effect such that the cause must take place before the effect

In the question, it is not clearly stated weather there was a divorce (the likely cause) takes place before the event

2) In the vent that the cause occurs, the effect must occur

Therefore, all those who are not married are expected to be deceased for there to be a cause and effect relationship

3) The cause and effect relationship must not be explicable by other factors

In the question, it is stated that those who were married were more likely to be active physically, maintain an healthy weight and were nonsmokers, which are factors that contribute to longevity.

You might be interested in
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
2 years ago
The sum of two numbers is 43. One number is five less than three times the other number. What is the largest number?
PolarNik [594]

Answer:

31

Step-by-step explanation:

Let the numbers be x and y.

"The sum of two numbers is 43." gives us the first equation.

x + y = 43

"One number is five less than three times the other number." gives us the second equation.

y = 3x - 5

Now we solve the system of two equations below.

x + y = 43

y = 3x - 5

Since the second equation is already solved for y, we will use the substitution method. We substitute 3x - 5 for y in the first equation.

x + y = 43

x + 3x - 5 = 43

4x - 5 = 43

4x = 48

x = 12

The first number is 12. Now we find the second number.

x + y = 43

12 + y = 43

y = 31

The larger number is 31.

4 0
2 years ago
Read 2 more answers
SOMEEEEONEEE pls help pls and thx :)
alekssr [168]

1) The sculptor created a marble basin with an approximate volume of 94,509.6 cubic centimeters -  Option D, 2) The approximate area of the heart-shaped cake is 283 square inches - Option B, 3) The length of the wooden frame around the window is 94.3 inches - Option B.

In this question we should make use of geometric formulas for volumes and areas and key information from statement in order to find the right choices.

1) In this case, the volume occupied by the marble water basin (V), in cubic centimeters, by subtracting the volume of the hemisphere from the volume of the cylinder:

V = \pi\cdot R^{2}\cdot h - \frac{2\pi}{3} \cdot r^{3} (1)

Where:

  • R - Radius of the cylinder, in centimeters.
  • h - Height of the cylinder, in centimeters.
  • r - Radius of the cylinder, in centimeters.

If we know that R = 30\,cm, h = 45\,cm and r = 25\,cm, then the volume of the marble is:

V = \pi \cdot (30\,cm)^{2}\cdot (45\,cm) - \frac{2\pi}{3}\cdot (25\,cm)^{3}

V \approx 94509.579\,cm^{3}

The right choice is D.

2) To determine the approximate surface area of the cake covered in red frosting (A_{s}), in square inches, we need to find the sum of the surface area of the entire circle and the surface area of the square:

A_{s} = l^{2} + 2\cdot l\cdot h + \frac{\pi}{4}\cdot D^2 + \pi \cdot D\cdot h (2)

Where:

  • l - Side length of the square, in inches.
  • h - Height of the cakes, in inches.
  • D - Diameter of the cakes, in inches.

If we know that l = 9\,in, h = 3\,in and D = 9\,in, then the <em>approximate</em> area covered in red frosting:

A_{s} = (9\,in)^{2} + 2\cdot (9\,in)\cdot (3\,in) + \frac{\pi}{4}\cdot (9\,in)^{2} + \pi \cdot (9\,in)\cdot (3\,in)

A_{s} \approx 283.440\,in^{2}

The right choice is B.

3) The frame around the window is found by means of the following perimeter formula (s), in inches:

s = \pi\cdot r + 2\cdot h + 2\cdot r (3)

Where:

  • r - Radius, in inches.
  • h - Height of the rectangle, in inches.

If we know that r = 9\,in and h = 24\,in, then the length of the frame around the window is:

s = \pi\cdot (9\,in) + 2\cdot (24\,in) + 2\cdot (9\,in)

s \approx 94.274\,in

The right choice is B.

We kindly invite to see question on volumes: brainly.com/question/1578538

7 0
1 year ago
Logan starts an IRA (Individual Retirement Account) at the age of 28 28 to save for retirement. He deposits $400 $ ⁢ 400 each mo
Valentin [98]

Answer:

A) Total amount deposited over the length of investment = $177600

B) Interest accrued upon retirement = $1,043,678.01

Step-by-step explanation:

From the question, we can see that he started the savings at the age of 28 and ended when he retired at the age of 65. Thus, number of years = 65 - 28 = 37 years

We are told he deposited $400 each month and that upon retirement it had grown to $1,161,278.01.

Since he deposited $400 each month, in a year which has 12 months, he deposited;

Amount deposited each year = 12 × 400 = $4800

Now, it took 37 years before he retired which was the point at which he stopped the deposit.

Thus;

Total Amount deposited upon retirement = Amount deposited each year × number of years he deposited.

Thus;

Total amount deposited over the length of investment upon retirement = 4800 × 37 = $177600

Now,we have seen that his retirement savings reads $1,161,278.01.

Thus is way more than the deposits he made throughout his work years.

This means there was interest on the money.

Interest = $1,161,278.01 - $177600

Interest = $1,043,678.01

8 0
1 year ago
A coin was tossed 60 times and the coin landed on Heads 35 times. What proportion of the time did the coin land on Heads?
SVETLANKA909090 [29]

Answer: Hence, the proportion of head lands obtained from the total number of tosses is 0.583

Step-by-step explanation:

Given the following :

Total number of coin tosses = 60

Total number of times coin landed on head = 35

Proportion of head landings obtained :

Total number of head landings obtained / total number of coin tosses

Proportion of head landing obtained :

= 35 / 60 = 7 / 12 = 0.5833

4 0
2 years ago
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