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Zigmanuir [339]
2 years ago
8

Uta invests an amount into a compound interest investment account that pays 6% a year. After six years, she withdraws her total

balance of $500. Using the formula A = P (1 + r) Superscript t, how much money did Uta initially invest?
$180.00
$320.00
$352.48
$471.70
Mathematics
2 answers:
AnnZ [28]2 years ago
6 0

Answer: $352.48

Step-by-step explanation:

Hi, to answer this question we have to apply the formula:

A = P (1 + r)^t

Where  

A: total balance after invest

P: principal amount invested

r = interest rate (in decimal form)

t = time (years)

Replacing with the values given:

500= P (1+0.06)^6

Solving for P:

500 = P (1.06)^6

500 / ( (1.06)^6)=P

500 / 1.4185 =P

$352.48= P

steposvetlana [31]2 years ago
4 0

Answer:

352.48

Step-by-step explanation:

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Kazeer [188]
If we take it that, the total amount is say hmmm "x"
then one can say that \bf \begin{cases}
\cfrac{2}{5}x\impliedby &\textit{no horns}\\\\
\cfrac{1}{7}x\impliedby &\textit{one horn}\\\\
\cfrac{1}{3}x\impliedby &\textit{two horns}\\\\
26\impliedby &remaining
\end{cases}
\\\\\\
\textit{so the total is really }\quad \cfrac{2}{5}x+\cfrac{1}{7}x+\cfrac{1}{3}x+26

add up the fractions of "x" and the constant of 26

4 0
2 years ago
Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005:25, 34, 46, 37, 33, 42
elixir [45]

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005

The data A={25, 34, 46, 37, 33, 42, 40, 37, 34, 49, 73, 46, 45, 45}  

To find : Modified box plot for this distribution?

Solution :

Arranging the data from lowest to highest,

{25,33,34,34,37,37,40,42,45,45,46,46,49,73}  

Find the median of the data  

As the data is even numbers so the median is

M=\frac{40+42}{2}=\frac{82}{2}=41

Median = 41

For Box plot Graph,

q_1=Q(A,0)

q_1=25

q_2=Q(A,0.25)

q_2=34.75

q_3=Q(A,0.5)

q_3=41

q_4=Q(A,0.75)

q_4=45.75

q_5=Q(A,1)

q_5=73

Plotting the Box plot of the data.

Refer the attached figure below.

8 0
2 years ago
Read 2 more answers
Sue played four games of golf for these games her modal score was 98 and her mean score was 100 her range of score was 10 what w
earnstyle [38]

Answer : Remaining two observation becomes 97 and 107.

Explanation :

Since we have given that

Mean = 100

Modal value = 98

Range = 10

As we know that ,

Range = Highest-Lowest

Let highest observation be x

Let lowest observation be y

So equation becomes x-y=10 ----equation 1

So, observation becomes

x,98,98,y

Now, we use the formula of mean i.e.

Mean = \frac{\text{Sum of observation}}{\text{N.of observaton}}

So, mean =\frac{x=98=98+y}{4}=400\\\frac{196+x+y}{4}=100\\x+y=400-196\\x-y=204

So our 2nd equation becomes

x+y=204

On using elimination method of system of linear equation on these two equation we get,

x=97

and

x+y=204\\y=204-x\\y=204-97\\y=107

Hence , remaining two observation becomes 97 and 107.

8 0
2 years ago
A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts. About 15.4% of the mixed nuts in a batch ar
Elan Coil [88]

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

\frac{part}{whole} = \frac{percent}{100}

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

\frac{77}{x} = \frac{15.4}{100}

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

4 0
2 years ago
Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and
Black_prince [1.1K]

Answer:

0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

Step-by-step explanation:

The random variable X is normally distributed with a mean of 21 and standard deviation of 7

;

X ~ N(μ = 21 ; σ = 7)

X ~ N(21, 7)

Probability that a trial lasted atleast 24 days :

P(X ≥ 24) :

The standardized score :

Z = (x - μ) / σ ; (24 - 21) / 7 ; 3 / 7 = 0.4286

Hence,

P(Z ≥ 0.4286) = 0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

6 0
2 years ago
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