Answer:
Step-by-step explanation:
Sample size = 95
X=cash carried by the persons
x bar = 8.00
s = sample std dev = 2.50
Std error = 
Hence Z score would be


-0.00
b) 
c) 95% conf interval margin of error = ±
=±0.54782
Confi interval = (8-0.5027, 8+0.5027)
= (7.4923, 8.5027)
C)If conf level increases, then width of interval would increase since critical value would increase.
If sample size increases std error would decrease and hence margin of error.
So interval would decrease.
Answer:
The answer is option (b), y=-5/2x+4
Step-by-step explanation:
The slope intercept form is a way of expressing the equation of a straight line; where there are two variables that vary in a linear form. The equation is always of the form; y=mx+c
Where;
- y and x represents the variables on the y and x axis respectively
- m is a real number representing the slope
- c is also a real number representing the y-co-ordinate, where the line intercepts the y-axis
Solving for y in 10x+4y=16
(4y)/4=(-10x)/4+(16/4)
The answer is y=-5/2x+4, option (b)
Answer:
6.33... and 0.333...
Step-by-step explanation:
The quadratic formula is
.
It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions. Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

We will now solve for the plus and the minus.
The plus,,,
and the minus...

Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
P(A U B U C) = 0.53
4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).