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lara31 [8.8K]
2 years ago
10

Kaitlyn gave 1/2 of her candy bar to arianna. arianna gave 1/3 of the candy she got from kaitlyn to cameron. what fraction of a

candy bar did cameron get?
Mathematics
1 answer:
sukhopar [10]2 years ago
5 0
Let the total candy bar be represented by x.

Amount of chocolate Kaitlyn gave to Arianna = \frac{1}{2}x

Amount of chocolate Arianna gave Cameron 

= \frac{1}{3} rd <span>of the candy she got from Kaitlyn to Cameron

= </span>\frac{1}{3} × \frac{1}{2}x

= \frac{1}{3}* \frac{1}{2} x  =  \frac{1}{6} x

Hence, Cameron got \frac{1}{6} th of the original chocolate.
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5 minutes

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9/6=40 mins per patient

8/6=45 mins per patient

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-120 ÷ 15 = -8.

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The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur
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In geometry, similar figures are those whose ratios of the  corresponding sides are equal and the corresponding  angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.
 
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                                    = 8/7
The square of this ratio is the ratio of the areas of the figure. If we let x be the area of the smaller figure then, 
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The value of x from the equation is 147 mm². 

The area therefore of the smaller figure is 147 mm².
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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
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Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
2 years ago
A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
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Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

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=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

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=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

8 0
2 years ago
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