Answer:
In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.
In J/g.°C - 1.005 J/g °C
In kcal/ kg °C 0.240 kcal/kg °C
In Btu/lbm-°F 0.240 Btu/lbm degree F
Step-by-step explanation:
given data:
specific heat of air = 1.005 kJ/kg °C
In kJ/kg.K
1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.
In J/g.°C
In kcal/ kg °C
For kJ/kg. °C to Btu/lbm-°F
Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.
1.005 kJ/kg C = 0.240 Btu/lbm degree F
Answer:
<h2>Second choice.</h2>Step-by-step explanation:
The given inequality is
Let's solve for
Basically, the solution of the given inquality is set with all real numbers which are equal or less than -8. So, the solution must indicate a blue line starting at -8 pointing to its left.
Therefore, the second choice represents the solution to the given inequality.
A.
Let Annie's weight be = a
Let Benjie's weighs = b
Let Carmen's weight be = c
One day Annie weighed 24 ounces more than Benjie, equation forms:
......(1)
Benjie weighed 3 1/4 pounds less than Carmen.
In ounces:
1 pound = 16 ounces
pounds =
ounces
or
......(2)
Now adding (1) and (2), we get
a+b=b+24+c-52
=>
This gives Annie weighs 28 ounces less than Carmen.
B.
We cannot know anyone's actual weight, as we only know their relative weights.