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Alex787 [66]
2 years ago
10

Erik drives 19.2 miles in 16 minutes.

Mathematics
1 answer:
Kipish [7]2 years ago
7 0
Bruh it clearly says 65 mph so that’s the answer
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Point T is at (–3, 7). What are the coordinates of point T' after Ry-axis ∘ Rx-axis?
dimaraw [331]

Given:

The point is T(-3,7).

To find:

The image T' after R_{y-axis}\circ R_{x-axis}.

Solution:

R_{y-axis}\circ R_{x-axis}, it means reflection across x-axis is followed by reflection across y-axis.

If a point is reflected across the x-axis, then

(x,y)\to (x,-y)

T(-3,7)\to T_1(-3,-7)

Then point is reflected across the y-axis. So,

(x,y)\to (-x,y)

T_1(-3,-7)\to T'(3,-7)

Therefore, the coordinates of point T' are (3,-7).

6 0
2 years ago
What is the value of (5x²)³ + 16y divided by 4y for x=2 and y=3
Inessa05 [86]

Answer:

30 2/3

Step-by-step explanation:

First multiply the two exponents

Second solve 2^6

Third multiply 64 times 5 = 320

Then multiply 16 times 3

Then add sums together 368

Lastly multiply 4 times 3 then divide 368 by 12

I hope this helps :)

6 0
2 years ago
Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b
horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
Erica earned a total of $50,450 last year from her two jobs. The amount she earned from her job at the store was $1,250 more tha
Mariana [72]

Erica earned a total of $50,450 last year from her two jobs. The amount she earned from her job at the store was $1,250 more than four times the amount she earned from her job at the college.

Lets x be the amount she earned from here job at college

amount she earned at the store = 4 * amount earned at college + 1250

= 4x + 1250

Amount earned at college + amount earned at store = 50450

x + 4x + 1250 = 50450

5x + 1250 = 50450

Subtract 1250 from both sides

5x = 49200 (divide by 5)

x = 9840

she earn $9840 from her job at the college

5 0
2 years ago
100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag
Lelu [443]
The answer is 5/9. I showed a bit more work on the other post
7 0
2 years ago
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