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KATRIN_1 [288]
1 year ago
9

Suppose that we ask n randomly selected people whether they share your birthday. (a) Give an expression in terms of n for the pr

obability that no one shares your birthday (ignore leap years). (b) What is the least number of people we need to select so that the probability is at least 0.8 that at least one person shares your birthday? (Round your answer up to the nearest integer.) people
Mathematics
1 answer:
expeople1 [14]1 year ago
3 0

plz mark brainly

plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

plz?

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What is the sum of the polynomials?<br><br> (7x3 – 4x2) + (2x3 – 4x2)
AnnZ [28]

Answer:

9x3 – 8x2

Step-by-step explanation:

Simplify signs:

 

8x2 - 5x3 - 4x2 + 9x3

 

Combine like terms:

 

(8x2 - 4x2) + (9x3 - 5x3)

3 0
1 year ago
A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 2780 seats. The students
Over [174]

Answer:

1242 6th graders went on the trip.

Step-by-step explanation:

From the information given, you know that the theater has 2760 seats and that the students filled 45% of the seats, so to find the quantity of 6th graders that went on the trip, you have to calculate 45% of 2760:

2760*45%=1242

According to this, the answer is that 1242 6th graders went on the trip.

5 0
1 year ago
A large tank is partially filled with 100 gallons of fluid in which 20 pounds of salt is dissolved. Brine containing 1 2 pound o
Valentin [98]

Answer:

47.25 pounds

Step-by-step explanation:

\dfrac{dA}{dt}=R_{in}-R_{out}

<u>First, we determine the Rate In</u>

Rate In=(concentration of salt in inflow)(input rate of brine)

=(0.5\frac{lbs}{gal})( 6\frac{gal}{min})\\R_{in}=3\frac{lbs}{min}

Change In Volume of the tank, \frac{dV}{dt}=6\frac{gal}{min}-4\frac{gal}{min}=2\frac{gal}{min}

Therefore, after t minutes, the volume of fluid in the tank will be: 100+2t

<u>Rate Out</u>

Rate Out=(concentration of salt in outflow)(output rate of brine)

R_{out}=(\frac{A(t)}{100+2t})( 4\frac{gal}{min})\\\\R_{out}=\frac{4A(t)}{100+2t}

Therefore:

\dfrac{dA}{dt}=3-\dfrac{4A(t)}{100+2t}\\\\\dfrac{dA}{dt}=3-\dfrac{4A(t)}{2(50+t)}\\\\\dfrac{dA}{dt}=3-\dfrac{2A(t)}{50+t}\\\\\dfrac{dA}{dt}+\dfrac{2A(t)}{50+t}=3

This is a linear differential equation in standard form, therefore the integrating factor:

e^{\int \frac{2}{50+t}dt}=e^{2\ln|50+t|}=e^{\ln(50+t)^2}=(50+t)^2

Multiplying the DE by the integrating factor, we have:

(50+t)^2\dfrac{dA}{dt}+(50+t)^2\dfrac{2A(t)}{50+t}=3(50+t)^2\\\{(50+t)^2A(t)\}'=3(50+t)^2\\$Taking the integral of both sides\\\int \{(50+t)^2A(t)\}'= \int 3(50+t)^2\\(50+t)^2A(t)=(50+t)^3+C $ (C a constant of integration)\\Therefore:\\A(t)=(50+t)+C(50+t)^{-2}

Initially, 20 pounds of salt was dissolved in the tank, therefore: A(0)=20

20=(50+0)+C(50+0)^{-2}\\20-50=C(50)^{-2}\\C=-\dfrac{30}{(50)^{-2}} =-30X50^2=-75000

Therefore, the amount of salt in the tank at any time t is:

A(t)=(50+t)-75000(50+t)^{-2}

After 15 minutes, the amount of salt in the tank is:

A(15)=(50+15)-75000(50+15)^{-2}\\=47.25$ pounds

8 0
1 year ago
Tad and Janice are installing new wood floors in a house. Tad can install 144 square feet of flooring in three hours. Janice can
solong [7]

Answer:

1.) How many square feet of flooring can Tad install in eight hours? 384 square feet

2.) How many square feet of flooring can Janice install in five hours? 480 square feet

3.) If they each work for 12 hours, how many square feet of flooring can they install? 1,728 square feet.

I hope i helped alot :)

4 0
1 year ago
Read 2 more answers
Triangle PQR has coordinates P (2, 4), Q (-2, 4), R (0,-6).
alexdok [17]

Answer: P’ (5,10) , Q’ (-5,10) , R’ ( 0,-15)

Step-by-step explanation:

Just multiply 2.5 by the x,y

4 0
1 year ago
Read 2 more answers
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