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yKpoI14uk [10]
2 years ago
8

Over the course of a year,a tractor-trailer commutes 160,000 miles across America.Assuming a trucker changes his tires every 40,

000 miles,and that he starts with a brand new set of tires,how many sets of tires will he use in a year?
Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
8 0

Answer:

He will use 4 sets of tires in a year.

Step-by-step explanation:

This question can be solved by a rule of three.

We have that:

Each set of tires lasts 40,000 miles. How many sets are going to be needed for 160,000 miles. So:

1 set - 40,000 miles

x sets - 160,000 miles

40000x = 160000

x = \frac{160000}{40000}

x = 4

He will use 4 sets of tires in a year.

Nikolay [14]2 years ago
3 0
160,000 - 40,000= 120,000/4 = 3 sets of new tires in the first year and 4 every consecutive year.
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Alissa has $360 for guitar lessons. She pays $25 for each lesson. How many lessons has she attended, if she still has $85 left?
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What percent of 137.4 is 96?
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Find the volume of the composite solid. Round to the nearest tenths. Radius:2 height:4
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2 years ago
Angela has the following coins in her pocket:
GaryK [48]

Answer:

  • There are 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

  • (10p, 1p)
  • (10p, 50p)
  • (10p, 2p)
  • (10p, 20p)

2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

  • (1p, 50p)
  • (1p, 2p)
  • (1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

  • (50p, 2p)
  • (50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

  • (2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

  • There are 4 + 3 + 2 + 1 = 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

7 0
2 years ago
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