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krok68 [10]
2 years ago
8

A 25 foot cable is stretched from the top of an antenna to an anchor point on the ground. How tall is the antenna if the anchor

point is 12 feet from the base of the antenna (rounded to the nearest foot)? A) 20 ft B) 21 ft C) 22 ft D) 23 ft
Mathematics
2 answers:
dexar [7]2 years ago
8 0

Answer:

22

Step-by-step explanation:

aliina [53]2 years ago
4 0
22ft . use pythagoras theorem getting 25ft as your hypotenuse and 12 feet as your adjacent,which will give you a height of 21.9317122ft which when rounded off to nearest foot is 22ft a.
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Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
2 years ago
Josiah has a 20% experimental probability of hitting the snooze button any morning when his alarm goes off. When he hits the sno
Citrus2011 [14]

Answer:

6 times

Step-by-step explanation:

There are two events here:

1. Probability to hit snooze button= P(A) = 20%. Also mean P(A') = 80%

2. The probability to miss the bus= B

If Josiah hits the snooze button (A is happen), he misses the bus(B) 25% of the time. It mean P(B | A) = 25%

If Josiah doesn't hit the snooze button (A didn't happen), he won't miss the bus. It mean P (B | A') = 0%

If alarm woke Josiah 120 times , expected times that Josiah miss the bus will be:  

P(B | A)* 120 * P(A) + P (B | A') * 120 * P(A') = 25%*20%*120 + 0% * 75%*120 = 6 times

3 0
2 years ago
The following histogram summarizes the number of points Nate has scored each game this season.
Ludmilka [50]

Answer:8/25

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
) The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students
katen-ka-za [31]

Answer:

The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549

Step-by-step explanation:

We are in posessions of the sample's standard deviation. So we use the student's t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975([tex]t_{975}). So we have T = 2.0930

The margin of error is:

M = T*s = 2.0930*0.16 = 0.3349.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 2.92 - 0.3349 = 2.5851

The upper end of the interval is the sample mean added to M. So it is 2.92 + 0.3349 = 3.2549

The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549

4 0
2 years ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
2 years ago
Read 2 more answers
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