Answer: f(2) = 4
Step-by-step explanation:
F(x) and g(x) are said to be continuous functions
Lim x=2 [3f(x) + f(x)g(x)] = 36
g(x) = 2
Limit x=2
[3f(2) + f(2)g(2)] = 36
[3f(2) + f(2) . 6] = 36
[3f(2) + 6f(2)] = 36
9f(2) = 36
Divide both sides by 9
f(2) = 36/9
f(2) = 4
Answer:
6 times
Step-by-step explanation:
There are two events here:
1. Probability to hit snooze button= P(A) = 20%. Also mean P(A') = 80%
2. The probability to miss the bus= B
If Josiah hits the snooze button (A is happen), he misses the bus(B) 25% of the time. It mean P(B | A) = 25%
If Josiah doesn't hit the snooze button (A didn't happen), he won't miss the bus. It mean P (B | A') = 0%
If alarm woke Josiah 120 times , expected times that Josiah miss the bus will be:
P(B | A)* 120 * P(A) + P (B | A') * 120 * P(A') = 25%*20%*120 + 0% * 75%*120 = 6 times
Answer:
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
Step-by-step explanation:
We are in posessions of the sample's standard deviation. So we use the student's t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.0930
The margin of error is:
M = T*s = 2.0930*0.16 = 0.3349.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.92 - 0.3349 = 2.5851
The upper end of the interval is the sample mean added to M. So it is 2.92 + 0.3349 = 3.2549
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
Answer:
Anna's walk as a vector representation is
and refer attachment.
Step-by-step explanation:
Let the origin be the point 1 from where Ann start walking.
Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,
Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)
Ann walk as a vector representation is 
Thus, Anna's walk as a vector representation is 