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SSSSS [86.1K]
2 years ago
6

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

g contains exactly the same weight. But if more than 10% of bags are over-filled then they stop production to fix the machine. They define over-filled to be more than 1 ounce above the weight on the package. The engineer weighs 153 bags and finds that 41 of them are over-filled. He plans to test the hypotheses H 0 : p = 0.1 versus H a : p > 0.1. What is the test statistic? z = (Please round your answer to two decimal places if necessary.)
Mathematics
1 answer:
mart [117]2 years ago
7 0

Answer:

Step-by-step explanation:

Download docx
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Describe the graph represented by the equation r=5/(3+2 sin theta).
Yuki888 [10]
We have the following equation:

r= \frac{5}{3+2sin(\theta)}

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse: 

The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
C(0, -2)

2. Length of major axis:

The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>

6 \ units

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

4 \ units

4. Foci:

Let's find c as follows:

c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}

Then the foci are:

f_{1}=(0, \sqrt{5}-2)

f_{2}=(0, -\sqrt{5}-2)

8 0
2 years ago
The base b(t)b(t)b, (, t, )of a triangle is decreasing at a rate of 131313 millimeters per minute and the height h(t)h(t)h, (, t
dem82 [27]

Answer:

  8.5 square mm per minute

Step-by-step explanation:

A = 1/2bh

A' = (1/2)(b'h +bh') . . . . differentiating with respect to time

A' = (1/2)((-13)(1) +(5)(6)) = (1/2)(17) = 8.5 . . . . mm²/min

The area is increasing at the rate of 8.5 mm²/min.

_____

<em>Numerical solution</em>

Consider the triangle dimensions .01 minutes before and after the time of interest.

  before: base = 5 + 0.13 = 5.13 mm; height = 1 - 0.06 = 0.94 mm. area = 2.4111 mm²

  after: base = 5 -0.13 = 4.87 mm; height = 1 +.06 = 1.06 mm. area = 2.5811 mm²

Average rate of change in that period is

  (2.5811 -2.4111)/0.02 = .17/.02 = 8.5 . . . . mm²/min

_____

<em>Comment on the numbers</em>

Note that we have assumed the base is decreasing at 13 mm/min. Quite often, division bars get lost on Brainly, so we're not sure this isn't 1/3 mm/min. At the assumed rate, the triangle will disappear in 5/13 minutes, about 23.08 seconds, when the base becomes zero. Of course, it only came into existence 1/6 minute (10 seconds) ago, when the height became non-zero.

3 0
2 years ago
Holly has watched 39% of a movie that is 122 minutes long. Which is the best estimate for the number of minutes of the movie tha
Anna007 [38]
48 minutes
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Welcome
5 0
2 years ago
Read 2 more answers
You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability
Feliz [49]

Answer:

The probability that a randomly chosen code starts with M and ends with E is 0.05 ....

Step-by-step explanation:

According to the given statement we have to make five letter code from  A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.

Thus the probability of picking the first letter M = 1/5

After that we require the sequence (not E, not E, not E) which is equal to:

= 3/4 * 2/3* *1/2

= 1/4

Now multiply 1/5 and 1/4

1/5 * 1/4

= 1/20

= 0.05

Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....

4 0
2 years ago
Which identity could be the missing step to verify the identity (cos theta)(csc theta)=cot theta
N76 [4]
(cosx)(cscx) = cotx
cscx = 1/sinx
(cosx)(1/sinx) = (cosx/sinx)
cosx/sinx = cotx

Basically, I noticed that cscx is equivalent to 1 divided by sinx, and then multiplied that fraction by cosx, which got me cosx/sinx. Your quotient identities will tell you that cosx/sinx = cotx
5 0
2 years ago
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