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ollegr [7]
1 year ago
15

Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?

Mathematics
1 answer:
kirill [66]1 year ago
8 0

Answer:

From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.

Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y – 6).

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What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp
finlep [7]

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

4 0
1 year ago
Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.
lianna [129]

Answer:

A

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

so

=2.6334 x 10-5

7 0
1 year ago
Given: The coordinates of triangle PQR are P(0, 0), Q(2a, 0), and R(2b, 2c).
masha68 [24]

Answer:

The line containing the midpoints of two sides of a triangle is parallel to the third side ⇒ proved down

Step-by-step explanation:

* Lets revise the rules of the midpoint and the slope to prove the

  problem

- The slope of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid-point of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

* Lets solve the problem

- PQR is a triangle of vertices P (0 , 0) , Q (2a , 0) , R (2b , 2c)

- Lets find the mid-poits of PQ called A

∵ Point P is (x1 , y1) and point Q is (x2 , y2)

∴ x1 = 0 , x2 = 2a and y1 = 0 , y2 = 0

∵ A is the mid-point of PQ

∴ A=(\frac{0+2a}{2},\frac{0+0}{2})=(\frac{2a}{2},\frac{0}{2})=(a,0)

- Lets find the mid-poits of PR which called B

∵ Point P is (x1 , y1) and point R is (x2 , y2)

∴ x1 = 0 , x2 = 2b and y1 = 0 , y2 = 2c

∵ B is the mid-point of PR

∴ B=(\frac{0+2b}{2},\frac{0+2c}{2})=(\frac{2b}{2},\frac{2c}{2})=(b,c)

- The parallel line have equal slopes, so lets find the slopes of AB and

  QR to prove that they have same slopes then they are parallel

# Slope of AB

∵ Point A is (x1 , y1) and point B is (x2 , y2)

∵ Point A = (a , 0) and point B = (b , c)

∴ x1 = a , x2 = b and y1 = 0 and y2 = c

∴ The slope of AB is m=\frac{c-0}{b-a}=\frac{c}{b-a}

# Slope of QR

∵ Point Q is (x1 , y1) and point R is (x2 , y2)

∵ Point Q = (2a , 0) and point R = (2b , 2c)

∴ x1 = 2a , x2 = 2b and y1 = 0 and y2 = 2c

∴ The slope of AB is m=\frac{2c-0}{2b-2a}=\frac{2c}{2(b-c)}=\frac{c}{b-a}

∵ The slopes of AB and QR are equal

∴ AB // QR

∵ AB is the line containing the midpoints of PQ and PR of Δ PQR

∵ QR is the third side of the triangle

∴ The line containing the midpoints of two sides of a triangle is parallel

  to the third side

6 0
1 year ago
You are having a pizza-making party. You will need 6 ounces of dough and 4 ounces of sauce for each person at the party (includi
Tcecarenko [31]

Answer:

78 ounces of dough

52 ounces of sauce

12 guests are coming (not including you)

Step-by-step explanation:

13x6=78

13x4=52

78+52=130 ounces

6 0
1 year ago
A carpenter charges $720 for 18 hours of work. She charges the same amount of money for each hour of work. Which table shows the
Ivan

Answer: 1h=$40

18h=$720

Step-by-step explanation:

for 18hrs she charged $720

For 1hr= $720/18

For 1hr=$40

3 0
2 years ago
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