Answer:
<h2>Height (h) =54.6mm</h2>
Step-by-step explanation:
Given :
Base (b) = 7.7mm
Area (a) = 210.21mm^2
Height (h) = ?

Answer:
1.4in
Step-by-step explanation:
Length of Photo = 4in
Width of Photo = 3in
Unknown:
Value of X = ?
Solution:
Follow these steps:
Area of a rectangle = l x w
Since the photo is a rectangle; area of photo:
Area of photo = 4in x 3in = 12in²
For the area of the ad;
Length of ad = 4 + x
Width of ad = 3 + x
Given that,
the area of the photo =
area of ad
12in² =
area of ad
Area of ad = 24in²
Area of the ad;
(4 + x) (3 + x) = 24
12 + 4x + 3x + x² = 24
12 + 7x + x² = 24
x² + 7x = 24 - 12
x² + 7x = 12
x² + 7x - 12 = 0
Using the almighty formula where
a = 1, b = 7 and c = -12
x = 
x =
or ![\frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}](https://tex.z-dn.net/?f=%5Cfrac%7B-7%20-%20%5Csqrt%5B%5D%7B-7%5E%7B2%7D%20-%204x1x-12%20%7D%20%7D%7B2x1%7D)
x = 1.4 or -8.4
therefore the answer is 1.4in
x is 1.4in
Answer:
6
Step-by-step explanation:
18×(3/6) = 918×(1/6) = 318×(2/6) = 6
We can use t=x^2 to solve this
Once we do that we will have simple square equation which we know how to solve.
t^2 + 3t + 2 = 0
t1 = -1
t2 = -2
x1 = √-1 = i
x2 = -i
x3 = √-2 = i√2
x4 = -i√2
Make sure you know that i^2 = -1 and (-i)^2 = -1 which gives us solutions we got...