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1 year ago

Help me please fvfbvtne d f vrgvbv

Mathematics

2 answers:

Ivenika [448]1 year ago

8 0

Answer:

<h2>Height (h) =54.6mm</h2>

Step-by-step explanation:

Given :

Base (b) = 7.7mm

Area (a) = 210.21mm^2

Height (h) = ?

$Area = \frac{base\times height}{2} \\\\210.21= \frac{7.7\times h}{2} \\\\210.21\times2 = 7.7\times h\\\\420.42 = 7.7 h\\\\\frac{420.42}{7.7}=\frac{7.7h}{7.7}\\\\54.6 =h\\\\h=54.6$

Nikitich [7]1 year ago

8 0

Answer:

60.1 mm

Step-by-step explanation:

The formula for the area of a triangle of base b and height h is A = (1/2)(b)(h).

We are to find the height of the given triangle, so solve this last equation for h:

2A = (b)(h), or h = 2A/b

Substituting 210.21 mm^2 for A and 7.7 mm for b, we get:

2(210.212 mm^2)

h = --------------------------- = 60.1 mm

7 mm

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The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1 0.1702

28.5 1.0252

28.8 0.5077

29.4 0.0127

29.8 0.0827

30.1 0.3452

30.6 1.1827

----------------------------------------

236.1 3.4088

Mean = 236.1 / 8 = 29.51

$S_{x}=\sqrt{3.4088/(8-1)}=0.6978$

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

$t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861$

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

$t$

Finding in the t distribution table α=0.05 with df=7, we have

$t_{0.05,7}=2.365$

$t>-t_{0.05,7}$ = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0

2 years ago

If 2x+9<32 then x could be

Y_Kistochka [10]

Answer:

x < 11.5

Step-by-step explanation:

2x + 9 < 32

(2x + 9) - 9 < 32 - 9

2x < 23

2x/2 < 23/2

x < 11.5

3 0

2 years ago

Read 2 more answers

A library buys 36 English books, 48 Science books and 72 Mathematics books. The thickness of each book is the same. Now, the lib

fomenos

Answer:

Step-by-step explanation:

The GCF of 36, 48, and 72 is 12 so there will be 36 / 12 = 3 stacks of English books, 48 / 12 = 4 stacks of science books and 72 / 12 = 6 stacks of math books for a total of 3 + 4 + 6 = 13 stacks.

5 0

2 years ago

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Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100

lara [203]

Answer:

the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100 2^(20 by 3)

= 10159.36

If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

3 0

1 year ago

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Which pairs of angles in the figure below are vertical angles?

ch4aika [34]

Answer: Option A and Option C.

Step-by-step explanation:

For this exercise it is important to know the definition of "Vertical Angles".

When two lines intersect or cross, there are a pair of angles that share the same vertex and they are opposite each other. This pair of angles are known as "Vertical angles".

By definition, Vertical angles are congruent, which means that the have the equal measure.

In this case, you can observe in the picture provided in the exercise that the line TI and the line WN intersect each other at the point S.

You can identify that the pair of angles that are opposite to each other and share the same vertex are the shown below:

$\angle ISN$ and $\angle TSW$

$\angle TSN$ and $\angle ISW$

6 0

2 years ago

Help me please fvfbvtne d f vrgvbv​

Help me please fvfbvtne d f vrgvbv