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zvonat [6]
2 years ago
8

Suppose that after 10 years of service, 40% of computers have problems with motherboards (MB), 30% have problems with hard drive

s (HD), and 15% have problems with both MB and HD. What is the probability that a 10-year old computer still has fully functioning MB and HD?
Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Answer:

The probability that a 10-year old computer still has fully functioning MB and HD is 45%

Step-by-step explanation:

The probability of the union of two events, is equal to the sum of the individual probabilities of the two events, minus the probability of the intersection event.

That means that the probability of have a fully functional computer (PFC) is equal to the sum of probability of have a computer with a functional motherboards (PFMB) plus the probability of have a computer with a functional hard drives (PFHD), minus the probability of have a computer with both motherboards and hard drives functional (PBMH).

PFC = PFMB+PFHD-PBMH

  • Probability of functional motherboards (PFMB)

PFMB = 1 - probability of having problems with motherboards = 1 - 40 %

PFMB  = 1 - \frac{40}{100} = 1 - \frac{4}{10} = \frac{6}{10}

  • Probability of functional hard drive (PFHD)

PFHD = 1 - probability of having problems with hard drive = 1 - 30 %

PFHD = 1 - \frac{30}{100} = 1 - \frac{3}{10} = \frac{7}{10}

  • Probability of functional both (PFMH)

PFMH = 1 - probability of having problems with both = 1 - 15 %

PFMH = 1 - \frac{15}{100} = 1 - \frac{3}{20} = \frac{17}{20}

PFC = \frac{6}{10} + \frac{7}{10} - \frac{17}{20}

PFC = \frac{9}{20}

PFC = 0.45

<em>Multiply by 100 to get in in %</em>

The probability that a 10-year old computer still has fully functioning MB and HD is 45%

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saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

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Combining all the like terms, we get as

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=-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}

Option A is the correct answer.

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2 years ago
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<h2>Answer:</h2><h2>volume of the cylinder = 2πx^{3}</h2>

Step-by-step explanation:

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One: B

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Step-by-step explanation:

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There are only two numbers in the sample of 40 that are under 26. Both are 25. If you find more, make the adjustment. There are 2 more that are exactly 26 but they are not counted because the directions say "less than 26."

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x = 2/40 * 2000

x = 4000/40

x = 100

A

I don't know where 5 comes from. But it is not correct.

B

B should be the correct answer.

C

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D is not correct. The sample size would not be 40. It would have to be 2000 for D to be correct. So D is wrong.

E

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The think you must NOT do is count 1 as being prime. The prime numbers are 2 3 5 7 between 1 and 8. They break down as follows.

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The experimental value is 10% more than the theoretical value.

Discussion

Note: the problem may be one. This all depends on what you have been told about 1. I am using the exact wording of prime here. 1 is not a prime. It is also not a composite. So it has to be counted as part of the non primes.


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Answer:

We conclude that the new procedure will not decrease the population mean amount of time required to produce the part.

Step-by-step explanation:

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A random sample of 25 parts will be selected and the average amount of time required to produce them will be determined. The sample mean amount of time is = 43.118 hours with the sample standard deviation s = 5.5 hours

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SO, <u>Null Hypothesis</u>, H_0 : \mu \geq  45 hours   {means that the new procedure will remain same or increase the population mean amount of time required to produce the part}

<u>Alternate Hypothesis,</u> H_a : \mu < 45 hours   {means that the new procedure will decrease the population mean amount of time required to produce the part}

The test statistics that will be used here is <u>One-sample t test statistics </u>because we don't know about the population standard deviation;

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Therefore, we conclude that the new procedure will remain same or increase the population mean amount of time required to produce the part.

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