A) The population and sample mean are always the same ... in this case, it is 20.6 minutes.
<span>b) First convert the data to z-values: </span>
<span>P(X<18) = P(z < (18-20.6)/8.4) = P(z< -0.3095) </span>
<span>Now, using a Standard Normal table, look up z= -0.3095 </span>
<span>P(X<18) = 0.3785 </span>
<span>Hope that helps</span>
101, 102, 100, 100, 110, 109, 109 ,108, 109 average to 105.3
subtracting the mean from each number yields the below-
-4,-3,-5,-5,5,4,4,3,4
Squaring each number gives-
16,9,25,25,16,16,9,16
The average of these numbers is 12.89 to two decimal places, so your variance is 12.89
<span>The number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.
</span><span>
<span><span>
Spinner 1
Spinner 2
</span>
<span>
1 1
</span>
<span>
1 2
</span>
<span>
1 3
</span>
<span>
1 4
</span>
<span>
2 1
</span>
<span>
2 2
</span>
<span>
2 3
</span>
<span>
2 4 = NOT 1, AND 4
</span>
<span>
3 1
</span>
<span>
3 2
</span>
<span>
3 3
</span>
<span>
3 4 = NOT 1, AND 4
Only 2 outcomes have passed the given condition.</span></span></span>
Given:
Eighteen 2.5 gallon buckets are needed to fill a cistern with water.
To find:
The constant of variation.
Solution:
If y is directly proportional to x, then
Where, k is constant of variation.
In the given problem, water in cistern (w) is directly proportional to number of buckets (n).
(Capacity of each bucket is 2.5 gallons)
Therefore, the constant of variation is 2.5.
