Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = 
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;
Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;
Therefore, the z-score more than 2 × which is significant.
Answer:
quotient=2,731
Remainder=0
Step-by-step explanation:
893) 2,438,783 (2,731
- 1 786
---------
6527
- 6251
---------
2768
- 2679
-----------
893
- 893
---------
0
<span>On an indifference curve, all bundles give the same amount of utility. (32,8) gives a utility of
U(32,8)=32x8=256
If (4,y) is on the same indifference curve, then it must give the same utility. Hence,
256 = 4y
y=64
64 bananas</span>
Answer:
yes, it is possible to have the sum of square roots equal the square root of the sum of the radicands.
If either a or b equals zero, then the sums would be the same.
Since the square root of 0 is 0, adding it to a given radical would not change the radical. Also adding zero to the radicand would not change its value.
these are the right answer for E2020
Answer:
Step-by-step explanation:
The formula for <u>exponential growth</u> is y = ab^x.
To write this equation, we know it has to start with 48 (which is the variable a). We need to add the rate of growth. This is 11/6 (which is variable b). But we also need to account for the "every 3.5 years" part, so divide the x as an exponent by 3.5.
N(t) = 48 * 11/6^(t/3.5)
This equation is easy to test, and it's a good idea to test it after you write it. For example, after 3.5 years we know that it should have 48*11/6 branches. Does our equation work? Yes.
