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sergejj [24]
1 year ago
7

Data berikut ialah suhu yang dicatat untuk 5 hari.

Mathematics
1 answer:
murzikaleks [220]1 year ago
5 0

\frac{25 + 2 7 + 34 + 28 + 29}{5}

119.8

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44 students completed some homework and the histogram shows information about the times taken. Work out an estimate of the inter
Vilka [71]

Answer:

q1=11

q3= 33

Step-by-step explanation:

The data set has 44 number of students. The first quartile is 25 %  of the numbers in the data set . So

25 % of 44 = 25/100 * 44= 0.25 *44 = 11

So the first quartile lies at 11.

Similarly the third quartile lies at the 75 % of the numbers of the data set . So

75 % of 44 = 75/100 * 44= 0.75 *44 = 33

So the third quartile lies at 33.

5 0
2 years ago
How many pairs of whole numbers have a sum of 110
kap26 [50]

There are different definitions of "whole numbers".

Some define it as an integer (i.e. positive or negative) [some dictionaries]

Some define it as a non-negative integer. [most math definitions]

We will take the math definition, i.e. 0<= whole number < &infin;

To find pairs (i.e. two) whole numbers with a sum of 110, we start with

0+110=110

1+109=110

2+108=110

...

54+56=110

55+55=110

Since the next one, 56+54=110 is the same pair (54,56) as 54+56=110, we stop at 55+55=110  for a total of 56 pairs.

5 0
1 year ago
Kendra has a bowl containing 10 blue marbles, 15 yellow marbles, 5 green marbles, and 6 red marbles of the same size. She will r
Mice21 [21]
Given:
10 blue marbles ; 15 yellow marbles, 5 green marbles, 6 red marbles
A total of 36 marbles.

Probabilities:
1st marble: red = 6/36
2nd marble: yellow = 15/35

6/36 * 15/35 = 6*15 / 36*35 = 90/1260 = 1/14

The probability that Kendra will draw a red marble and then a yellow marble is 1/14.
6 0
2 years ago
A bar graph titled Album Type Sold per Year has year on the x-axis and number of albums sold on the y-axis. For C D s, in 2008 t
stira [4]

Answer:

True, True, False, True, False, True

Step-by-step explanation:

<u>CDs have a higher mean than digital</u>

<u />

Let's check.  CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33

Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67

CD's mean is higher.  Since you are dividing byt he same number you also could have just added the amount and found which was a larger number.  But yes, this is true.

<u>The range of digital is 800</u>

<u />

The range is the highest number inus the lowest number.  For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800.  So this is true.

<u>The median of CDs is 400. </u>

<u />

The median is the middle value for odd numbers of values, or the average of the two middle values.  6 total values means you have to take the third and fourth and average them.  in CDs the middle values are 800 and 600, the average is 700, so that is what the median is.  this is false.

<u>Both have the same interquartile range. </u>

<u />

Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those.  Then subtract the larger one fromt he smaller one.

IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400

IQR of digital is 700-300 = 400 so yes both are the same.

<u>Both have the same median</u>

<u />

We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400.  So no, the medians are not the same.

<u>Digital’s mean is around 467. </u>

<u />

We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.

8 0
2 years ago
Read 2 more answers
What are the domain, range, and asymptote of h(x) = 6x – 4? domain: {x | x is a real number}; range: {y | y &gt; 4}; asymptote:
Mkey [24]

Answer:

Step-by-step explanation:

The domain of a function is the set for which the function is defined. Our function is the function h(x) = 6x-4. This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.

The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.

Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.

4 0
1 year ago
Read 2 more answers
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