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2 years ago

Write the following inequality in slope intercept form. 6x + 2y ≤-46

2 answers:

7 0

Slope intercept form is y=mx+b
So we're solving the equation in the question for y.
First, we subtract 6x from both sides to get

2y<-46-6x. Then we divide both sides by 2 to get y alone.
Then the answer will be y<-46÷2 -6x÷2
FInal answer = y< -23-3x or y<-3x-23

Lelu [443]2 years ago

5 0

Solve for y
minus 6x both sides
2y<span>≤-2x-46
divide both sides by 2
y≤-x-23
</span>

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Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. A cereal company claims that th

Dmitrij [34]

Answer:

There is not sufficient evidence to warrant the rejection of the claim that the mean weight of cereal is atleast 14 oz

Step-by-step explanation:

The hypothesis for the test above will be stated as follows :

The claim to be tested is the alternative hypothesis, which is the negation of the Null hypothesis

H0 : μ < 14

H1 : μ ≥ 14

If the Null is rejected, then it means that the company's claim that the mean weight of its cereal being atleast 14 is valid ;

Then it means there is significant evidence to support the stance that the mean weight of cereal in the company's packet is atleast 14 oz.

3 0

1 year ago

Find the quantity q that maximizes profit if the total revenue, R(q), and total cost, C(q) are given in dollars by R(q)=3q−0.002

marysya [2.9K]

Answer:

The value of q that maximize the profit is q=200 units

Step-by-step explanation:

we know that

The profit is equal to the revenue minus the cost

we have

$R(q)=3q-0.002q^{2}$ ---> the revenue

$C(q)=200+2.2q$ ---> the cost

The profit P(q) is equal to

$P(q)=R(q)-C(q)$

substitute the given values

$P(q)=(3q-0.002q^{2})-(200+2.2q)$

$P(q)=3q-0.002q^{2}-200-2.2q$

$P(q)=-0.002q^{2}+0.8q-200$

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the value of q that maximize the profit

The y-coordinate of the vertex represent the maximum profit

using a graphing tool

Graph the quadratic equation

The vertex is the point (200,-120)

see the attached figure

therefore

The value of q that maximize the profit is q=200 units

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2 years ago

Which of the following functions is graphed below?

Pavlova-9 [17]

Answer:

Step-by-step explanation:

It is a piece-wise function, so you will have two equations and two different domains. x squared plus 3 represents the sort of parabola and x plus 4 represents a linear function. There is a reason why the point on the parabola is open when x is 4. That open sign means that the x value doesn't work for the equation. Therefore, x cannot be 4 for the parabola and the domain for it is x is less than 4. The point on the linear function is closed to show that 4 for x does work for the equation and graph. For the linear function, the domain for it is x is greater or equal to 4. Hope this helps!

8 0

2 years ago

Researchers want to determine if caffeine affects reaction time. They divide a sample of 150 people into 3 groups. Group 1 gets

11111nata11111 [884]

Answer:

One-way ANOVA

Step-by-step explanation:

One-way ANOVA(analysis of variance) a testing method in statistics that is used to compare the means of two or more independent samples, to check if the differences are statistically significant.

In this case, we have three groups which their various reaction time to caffeine is to be tested using the same testing method (amount of caffeine). Hence the appropriate test to use here is the one-way ANOVA

7 0

2 years ago

370 College freshmen were interviewed. 200 were registered for an Advanced Math class. 270 were registered for an English class

frozen [14]

Answer:

Step-by-step explanation:

To aid in understanding, draw three circles...

100 were registered for both Math and English.

50 were registered for both Sport and English but not Math.

70 were registered for Math, Sport, and English.

From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class

a. none signed up only for Maths (refer to attached document)

b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.

c. How many signed up for an English class and at least one other class?

From the venn diagram:

we could have an English class and maths class - 100

we could also have an a English class and sports - 50

Thus total is 150.

d. What is the total fee for all the students enrolled in classes

From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000

From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000

From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000

Total fees = $12,000 + $27,000 + $14,000 = $53,000

5 0

2 years ago