Given that the<span> iq scores for large populations are centered at 100.
To get what percent of these 78 students have scores above 100 we conduct a normal distribution probability of the data.
P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
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Where are the answer choices?
Hello,
a) | |PA|-π |>| |PB|-π | (see pic)
c) 3.14< x/113 <=π <22/7
==>3.14*113<x<22/7 * 113
==>354.82 <x < 355.14285
==>x=355
Answer 355/113=3,1415929203539823008849557522124
Sang grew more. and by 17/40 ( I could be wrong)
