HI THERE YO!!!!!!"Use Pythagorean Theorem to solve (a right triangle with the base being one of the side lengths and the height being the other side length. a^2 + b^2 = c^2
64^2 + 100^2 = length of diagonal ^2
4096 + 10000 = 14096
The length of the diagonal is the square root of 14096 or 118.727 meters (rounded to the thousandths place). "
Read more on Brainly -
brainly.com/sf/question/1737729the answer is credited to the user on brainly in the link
hope this helps!!
Let x <u>represent</u> the <u>number of cups</u> of Superfiber Will ate this week and let y represent the number cups of Fiber Oats he ate this week.
1. If in Superfiber cereal, there are 5 grams of fiber in one cup, then in x cups there are
grams of fiber.
2. If in Fiber Oats cereal, there are 4 grams of fiber in one cup, then in y cups there are
grams of fiber.
3. The total amount of fiber Will ate is
grams.
4. This week Will ate at least 30 grams of fiber. Then

Answer: correct choice is A.
2 inches wide
that means that the height of the large carton is 2 inches
find the volume of the carton
V=108 times volume of small box
V=108 times 1 times 2 time s3
V=648 in^2
height is 2
V=LWH
648=LW2 (note, this is not LW^2 but 2 times LW)
divie both sides by 2
324=LW
legnth of base is less than 36
div
we just need to find the values of legnth and width such that LW=324 and L<36 and that L or W is divisible by 3 (since each box is 3 inches long)
so lets factor 324
324=2*2*3*3*3*3
group them and find possible values for legnth and width less than 36 and divsible by 3
possible values
(L,W,H) possible values are
(27,12,2)
(18,18,2)
the possible dimentions are
27 by 12 by 2 or
18 by 18 by 2
Find the volume of the first figure, then find the volume of the second figure, then add them together.
V=lwh
V(1)=(15)(12)(6)
= 1,080in^3
V(2)=(12)(6)(6)
= 432in^3
--------------------------------------------
1,080+432= 1,512 in^3
--------------------------------------------
Your answer should be 1,512
Answer:
1st option: 113.04 cm³
Step-by-step explanation:
Volume of sphere= 
Volume of ornament
