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drek231 [11]
2 years ago
8

What is an acrostic poem for the word percent

Mathematics
1 answer:
Feliz [49]2 years ago
7 0
Proportion
Express
Rate
Commission
Equals
Number
Times
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Out of 40 chocolates, ram and i shared in the ratio 1:3 . how many chocolates did ram get?
Leviafan [203]
So ram had 10 chocolates and i had 30 chocolates

because 1:3= 10:30
=> 4= 40
4 0
2 years ago
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"a guest orders a drink that contains 1½ ounces of 80-proof vodka and 12 ounces of beer. approximately how many drinks does this
frosja888 [35]
A guest orders a drink = <span>1½ ounces of 80-proof vodka and 12 ounces of beer
it means it contains 2 drinks.
Because 3 ounces of 80 proof vodka is considered as 2 drinks and half of that will be considered as 1 drink, and 12 ounces of beer is considered as one drink so the total drinks this beverage contains is two drinks.</span>
7 0
2 years ago
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If n - 2y = 3y- n/m,find the value of n when y = 5 and m = -3
Gnom [1K]

Answer:

37 1/2

Step-by-step explanation:

n - 2y = 3y- n/m,

find the value of n when y = 5 and m = -3

--------

n-2*5=3*5-n/-3

n-10=15+n/3

n-n/3=15+10

2n/3=25

2n=3*25

n=75/2

n=37 1/2 or 37.5

5 0
2 years ago
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Which data set is least Likely to resemble a normal distribution?<br> Look at picture
kicyunya [14]

Answer: B) The heights of girls who live on a certain street in the city of Buffalo

Every answer choice starts with "the heights of all 14-year-old girls who", so we can ignore that part. Choice A describes the largest population while choice B describes the smallest population. In other words, choice A is very general and broad, while choice B is very specific and narrow. The more specific you get and the smaller the population is, the less likely its going to be normally distributed.

4 0
2 years ago
Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
enot [183]
Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15

to find x divide: 15/3=5

And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes 
7 0
2 years ago
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