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Veronika [31]
2 years ago
15

The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

the energy stored by the spring is 12 joules, what is the approximate weight of the spring in pounds?
Mathematics
2 answers:
Lesechka [4]2 years ago
8 0

Answer:

3.12 pound.

Step-by-step explanation:

Energy due to weight, w, of the spring = 0.9 × \sqrt{E} will be represented by

W=mg=0.9\sqrt{E}

If energy stored by the spring is 12 joules.

Then weight of the spring will be

m'g = w' = 0.9\sqrt{12}

             = 0.9 × 3.46

             = 3.12 pounds

The approximate weight of the spring  is 3.12 pound.

frutty [35]2 years ago
4 0
For this case we have the following equation:
 w = 0.9* \sqrt{E}
 Where,
 w: The weight of a spring in pounds
 E: the energy stored by the spring in joules.
 Substituting values we have:
 w = 0.9* \sqrt{12}
 Making the corresponding calculation:
 w=3.12
 Answer:
 
the approximate weight of the spring in pounds is:
 
w=3.12
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1 year ago
Evaluate the expression. P(9, 3) · P(5, 4)
boyakko [2]

Answer:

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Step-by-step explanation:

For this problem we want to find the following expressionÑ

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6 0
2 years ago
A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dim
Bingel [31]
We have the following dimensions:
w=wide
w+70=length

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leg₁=w
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Pythagoras theorem:
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w²+(w+70)²=130²

We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
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w=(-70⁺₋√(4900+24000)) / 2
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We have two possible solutions:
Solution 1

w=(-70-170)/2=-120   (this solution is not possible because the result is negative and it have no sense in this problem).

Solution 2

w=(-70+170)/2=50  (this is the right solution)

w=50
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ANSWER:  the length would be 120 u  (u=units of length ) and the wide would be 50 u.
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2 years ago
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