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1 year ago

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wes has six errands to run (picking up the dry cleaning, going to the grocery store, getting gas, going to the bank, going to th

e library, and going to the video store). he only haves time to run 3 errands this afternoon. how many different combinations of three errands could he choose to run?

2 answers:

dlinn [17]1 year ago

7 0

Answer: 120 different combinations .

Step-by-step explanation:

The combination of n things taking m things at a time is given by :-

$C(n,m)=\dfrac{n!}{m!(n-m)!}$

Given : The total numbers of errands = 6

Now, the combination of 6 errands taking 3 at a time is given by :-

$C(6,3)=\dfrac{6!}{3!(6-3)!}\\\\=\dfrac{6\times5\times4\times3!}{3!}=120$

Hence, he could choose to run 120 different combinations of three errands .

ss7ja [257]1 year ago

4 0

If you did 1*2*3*4*5*6 it's 720

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Hello

The answer is <span> 3 minutes speaking Polish and 2 minutes speaking Hungarian.

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2 years ago

Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 pe

timofeeve [1]

A,B,C,D i.e. all statements are true!

<u>Step-by-step explanation:</u>

According to question, Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 per week to cover her expenses. The inequality for above scenario will be :

$15x + 10y\geq 300$ where, x is number of necklaces & y is number of bangles.

A.

Lynn will meet her goal if she sells 12 bangles and 12 necklaces. i.e. x=12 and y=12 , putting values inequality : $15(12) + 10(12) = 300$ which follows inequality . True statement!

B.

Lynn will meet her goal if she sells 20 bangles and 6 necklaces.

putting values inequality : $15(6) + 10(20) = 290$ which follows inequality . True statement!

C.

Lynn will meet her goal if she sells 6 bangles and 12 necklaces. putting values inequality : $15(12) + 10(6) = 240$ , which follows inequality . True statement!

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1 year ago

Read 2 more answers

Ursula Works At A Print Shop. She Uses A Printer That Can Print 12 Pages Per Minute. Yesterday She Started Printing Flyers For A

BigorU [14]

Answer:

10:30 am.

Step-by-step explanation:

We have been given that Ursula uses a printer that can print 12 pages per minute.

Ursula started printing flyer for an order yesterday. Today at 8 am she continued working on the order, and by 9 a.m. she had 420 flyers for the order completed. The order was to print 1500 pages.

Let us find the number of pages left to print.

$\text{Number of the pages left to print}=1500-420$

$\text{Number of the pages left to print}=1080$

To find the time it will take to print 1080 pages we will divide number of pages left to print by number of pages printed per minute.

$\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{\frac{\text{12 pages}}{\text{minute}}}}$

$\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{12}\times \frac{\text{minute}}{\text{page}}}$

$\text{Time it will take to print 1080 pages}=90\text{ minutes}$

90 minutes will be 1.5 hours , so 1.5 hours after 9 am will be 10:30 am. Therefore, the job was finished at 10:30 am.

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1 year ago

One cube has an edge length 5 cm shorter than the edge length of the second cube. The volume of the smaller cube is 216 cm?. Wha

VLD [36.1K]

Answer:

The volume of the larger cube is $V=1,331\ cm^3$

Step-by-step explanation:

Let

x ---> the length of the smaller cube

y ---> the length of the larger cube

we know that

the volume of a cube is equal to

$V=b^3$

where

b is the length side of the cube

we have

$x=y-5$ ----> equation A

The volume of the smaller cube is 216 cm^3

so

substitute in the formula of volume

$216=x^3$

solve for x

$x=\sqrt[3]{216}\ cm$

$x=6\ cm$

<em>Find the value of y</em>

$x=y-5$

$6=y-5$

$y=6+5=11\ cm$

<em>Find the volume of the larger cube</em>

$V=y^3$

substitute the value of y

$V=11^3$

$V=1,331\ cm^3$

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2 years ago

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grandymaker [24]

Answer:

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Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

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So, Null Hypothesis, $H_0$ : $\mu$ = $20,000

Alternate hypothesis, $H_A$ : $\mu \neq$ $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean income

$\sigma$ = population standard deviation = $2,000

n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

3 0

2 years ago