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fenix001 [56]
2 years ago
14

Toby's Tiny Toys have fixed expenses of $53,900 for the production of their tiny toys. Toby's has a variable expense of $12.50 a

piece for each toy they produce, and they sell their toys for $16.50 a piece.How many tiny toys do they have to sell to reach their breakeven point?
Mathematics
1 answer:
ipn [44]2 years ago
6 0

The total cost of the factory will be the sum of its variable costs and it's fixed costs. The factory has fixed costs of $53,900 and variable costs of $12.50 per unit produced. Let x be the number of toy's produced by this Toby's Tiny Toys, then the total variable costs will be 12.50x. From this information we can gather that the cost function for this factory is,

C(x)=53\,900+12.50x.

On the other hand, if we let x be the number of toys sold, we can gather that at the selling price of 16.50, the revenue function will be ,

R(x)=16.50x.

Toby's Tiny Toys will reach their break even point when the total costs are equal to the total revenue. At this break even point ,we have that

R(x)=C(x)\\\implies 16.50x=12.50x+53\,900\\\implies 16.50x-12.50x=53\,900\\\implies 4x=53\,900\\\implies x=\frac{53\,900}{4} \\\implies x=134\,750.

The company has to sell 134 750 units to break even.

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Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

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Step-by-step explanation:

If we perform a hypothesis test, we can reject or not reject the null hypothesis.

To conclude that the tires have a decreased stopping distance (μ<215), we should state the null hypothesis H_0: \mu\ge 215 and then go on with the analysis to reject it (or not).

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The alternative hypothesis would be H_1: \mu, that would turn rigth if the null hypothesis is rejected.

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Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options,
ElenaW [278]

Answer:

These are the rectangular prisms that have a surface area greater than 140 square feet

6 feet by 5 feet by 4 feet

7 feet by 6 feet by 4 feet

8 feet by 3 feet by 7 feet

Step-by-step explanation:

The formula to find the surface area of a rectangular prism is SA=2(wl+hl+hw)

All you have to do is go through all the options given to you to figure out which retangular prisms have a surface area greater than 140 square feet.

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