Answer: The lower bound of confidence interval would be 0.116.
Step-by-step explanation:
Since we have given that
p = 13.2%= 0.132
n = 1105
At 90% confidence,
z = 1.645
So, Margin of error would be

So, the lower bound of the confidence interval would be

Hence, the lower bound of confidence interval would be 0.116.
Answer:
<h2>The reliability is 0.999999.</h2>
Step-by-step explanation:
The failure rate for a guided missile control system is 1 in 1,000.
Hence, the probability that the missile will not fail is
.
According to the new system, if the first fails, the second can take over.
There are two possibilities, either the first one will be fail or not.
If the first one will not fail, then the probability will be
= 0.999.
If the first one will fail, then the probability will be
.
The reliability of the modified missile is 0.999 + 0.000999 = 0.999999.
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
__
B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity
Dunno how to do the linear thing
anyway
9+5=14
14 units=all tents
98=all tents
98=14 units
divide by 14 both sides
7=1 unit
food=9 unit
1 unit=7
times 9
9 unit=63
retail=5 unit
1unit=7
times 5
5 unit=35
a. f+r=98
f/r=9/5 could be the system
b. 63 food tents
c. 35 retail tents