Answer:
Mark the point of intersection S of circles R and P, and construct line QS.
Step-by-step explanation:
In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.
You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Answer:
x = 1, y = 60
Step-by-step explanation:
Value of new-releases (x) = $20 each
Value of classic (y) = $8 each
Total budget = $500
Equation : 20x + 8y = 500
The librarian wants to purchase maximum DVDs. She can get more DVDs of classic movies for $8 as they are less costly.
Lets assume the librarian buys at least one new-release DVD.
x=1
20x + 8y = 500
8y + 20(1) = 500
y = 60
<em>Therefore, in a budget of $500, the librarian can purchase 60 classic movies and 1 new-release.</em>
!!
(a) The equation of the tangent line can be written as
.. 3(x +6) -4(y -8) = 0
.. 3x -4y = -50
.. y = (3/4)x +25/2 . . . the equation of the tangent line
(b) The point of tangency will be the intersection of the circle with the perpendicular line through the circle center, y = (-1/5)x. A graphing calculator shows that point to be
.. (9.81, -1.96)
= 6.37 * 10^4 = 637 * 10^2 = 63700
In short, Your Answer would be Option A
Hope this helps!
