Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer:
(x +sqrt(48)) (x-sqrt(48))
Step-by-step explanation:
sqrt = Square Root
sqrt(48) = 6.928
10x+6y=152
5x+3y=76
7x+12y=200
-20x-12y=-304
-13x=-104
x=8
40+3y=76
3y=36
y=12
There are 8 granola bars in a pack and 12 fruit rolls in a pack
Answer:
C! ITS C!!!
Step-by-step explanation:
