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2 years ago

An object was moving at a rate of 18.2 feet per second for 38.5 seconds. How far did the object travel?

Mathematics

1 answer:

lidiya [134]2 years ago

4 0

Answer:

700.7

Step-by-step explanation:

You're looking for distance. So all you have to do is 18.2 x 28.5 and you'll get your answer.

Hope this helps. :)

You might be interested in

An airline wants to evaluate the depth perception of its pilots over the age of fifty. A random sample of n = 14 airline pilots

Y_Kistochka [10]

Answer:

Step-by-step explanation:

Hello!

1) The objective is to evaluate the depth perception of pilots over the age of fifty.

To do so a sample of n=14 airline pilots over the age of fifty was taken, each of them was asked to judge the distance between two markers placed 20 feet apart, the pilot's error in judging the distance was recorded:

2.9, 2.6, 2.9, 2.6, 2.4, 1.3, 2.3, 2.2, 2.5, 2.3, 2.8, 2.5, 2.7, 2.6

Then the variable of interest is X: error in judging the distance between two markers placed 20 feet apart of one pilot. (feet)

Assuming that this variable has a normal distribution, with a standard deviation of σ= 1.4 feet

The hypothesis is that the mean error in-depth perception for the company's pilots over the age of fifty is greater than 2.1, symbolically: μ > 2.1

H₀: μ ≤ 2.1

H₁: μ > 2.1

α: 0.05

Since the variable has a normal distribution and the population standard deviation is known, the statistic to use for this test is the standard normal:

$Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)$

The sample mean is

X[bar]= ∑X/n= 34.90/14= 2.49

$Z_{H_0}= \frac{2.49-2.1}{\frac{1.4}{\sqrt{14} } } = 1.04$

The p-value for this test is 0.14917

Using the p-value approach, since it is greater than the significance level, the decision is to not reject the null hypothesis.

Then there is no evidence that the mean error in-depth perception for the company's pilots over the age of fifty is greater than 2.1 feet.

2) To construct the 90% confidence interval you have to use the same distribution as before, the formula for the interval under the standard deviation is:

[X[bar] ± $Z_{1-\alpha /2}$ * (δ/√n)]

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[2.49 ± 1.645 * (1.4/√14)]

[1.87; 3.11]

With a 90% confidence, you'd expect that the true mean of the error in-depth perception of the airline's pilots over fifty years old is contained in the interval [1.87; 3.11].

I hope you have a SUPER day!

7 0

2 years ago

Suppose that D(r) is a function which gives the population density, in hundreds of people per square mile, within r miles of the

borishaifa [10]

Answer:

a) T(r) = r.D(r)

b) 975 people per square mile.

Step-by-step explanation:

(a)

The units of D(r) are

$\frac{hundreds\;of\;people}{mile^2}$

when multiplying the density by the area we get the amount of people in that area, so

$T(r)=rmile^2D(r)\frac{hundreds\;of\;people}{mile^2}=rD(r)\;hundreds\;of\;people$

(b)

The average rate of change of T(r) over the interval [5,7] is

$\frac{T(7)-T(5)}{7-5}=\frac{7D(7)-5D(5)}{2}$

but D(7) = 350 and D(5) = 100, so

$\frac{7D(7)-5D(5)}{2}=\frac{7*350-5*100}{2}=975$

and the average rate of change of T(r) over the interval [5,7] is 975 people per square mile.

5 0

2 years ago

Solve for x in the equation x squared minus 12 x + 59 = 0. x = negative 12 plus-or-minus StartRoot 85 EndRoot x = negative 6 plu

fgiga [73]

Value of x is: $x=6\pm\sqrt{23}i$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2-12x+59=0$ and find value of x.

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values of a, b and c and finding the value of x

a=1, b=-12 and c=59

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(59)}}{2(1)}\\x=\frac{12\pm\sqrt{144-236}}{2}\\x=\frac{12\pm\sqrt{-92}}{2}\\x=\frac{12\pm\sqrt{92}i}{2}\\We\,\,know\,\sqrt{-1} \,\,is\,\,i\\x=\frac{12\pm2\sqrt{23}i}{2}\\x=\frac{2(6\pm\sqrt{23}i)}{2}\\x=6\pm\sqrt{23}i$

So, value of x is: $x=6\pm\sqrt{23}i$

Option B is correct option.

4 0

2 years ago

Read 2 more answers

Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op

Alex17521 [72]

Answer:

a) $P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

b) $P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(z>0.686)$

And we can find this probability using the complement rule, the normal standard table or excel and we got:

$P(z>0.686)=1- P(Z$

c) $P(46.8-1.5*1.75$

And we can find this probability with this difference:

$P(-1.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.5$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the velocities of a population, and for this case we know the distribution for X is given by:

$X \sim N(46.8,1.75)$

Where $\mu=46.8$ and $\sigma=1.75$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

Part b

$P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(z>0.686)$

And we can find this probability using the complement rule, the normal standard table or excel and we got:

$P(z>0.686)=1- P(Z$

Part c

$P(46.8-1.5*1.75$

And we can find this probability with this difference:

$P(-1.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.5$

6 0

2 years ago

The total cost of a shirt and a tie was $75.62. if the price of the shirt was $4.02 less than the tie, what was the price of the

kifflom [539]

--------------------------------------------
Define x:
--------------------------------------------
Let the tie be x
Tie = x
Shirt = x - 4.02

--------------------------------------------
Construct equation :
--------------------------------------------
The sum of the shirt and tie is $75.62
x + x -4.02 = 75.62
2x - 4.02 = 75.62
2x = 79.64
x = $39.82

--------------------------------------------
Find the cost of tie and shirt :
--------------------------------------------
Tie = x = $39.82
Shirt = x - $4.02 = $39.82 - $4.02 = $35.80

----------------------------------------------------------------------------------------
Answer: The price of the short is $35.80
----------------------------------------------------------------------------------------

5 0

2 years ago