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jeka57 [31]
2 years ago
10

There are 135 people in a sport centre. 77 people use the gym. 62 people use the swimming pool. 65 people use the track. 27 peop

le use the gym and the pool. 23 people use the pool and the track. 31 people use the gym and the track. 4 people use all three facilities. A person is selected at random. What is the probability that the person uses exactly one of the facilities?
Mathematics
1 answer:
umka21 [38]2 years ago
5 0

Answer:

The correct answer is \frac{2}{9}.

Step-by-step explanation:

There are 135 people in a sport centre.

Let the experiment be to pick a person from the sport centre who only uses exactly one of the facilities.

Total number of possible outcomes = 135

For the gym:

77 people use the gym.

27 people use the gym and the pool.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the gym are 77 - ( 27 + 31 + 4) = 15

For the swimming pool:

62 people use the swimming pool.

27 people use the gym and the pool.

23 people use the pool and the track.

4 people use all three facilities.

Total number of people using only the swimming pool are 62 - ( 27 + 23 + 4) = 8

For the tracks:

65 people use the track.

23 people use the pool and the track.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the tracks are 65 - ( 23 + 31 + 4) = 7

A person is selected at random.

Favorable outcomes = 7 + 8 + 15 = 30

Probability that the person uses exactly one of the facilities = \frac{Favorable}{Total} = \frac{30}{135}  = \frac{2}{9}.

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A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

7 0
2 years ago
Find the area of irregular figure ​
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Step-by-step explanation:

For square

A=bh

A=30(20)

A=60in²

For triangle

A=½bh

A=½(40)(30)

A=½(120)

A=60in²

Add

60+60=120in²

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How much water is in an empty glass that is 10cm high and has a diameter of 5cm
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Answer:

How much water is in an empty glass that is 10cm high and has a diameter of 5 cm ?

= 196,25 cm

Step-by-step explanation:

diameter = 5 cm

radius = 1/2 × diameter

radius = 1/2 × 5 = 2,5

How much water is in an empty glass that is 10cm high and has a diameter of 5 cm?

= π × r × r × high

= 3,14 × 2,5 × 2,5 × 10

= 196,25 cm

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2 years ago
While standing on a highway overpass, Jennifer wonders what proportion of the vehicles that pass on the highway below are trucks
Assoli18 [71]

Answer:Obtain a systematic sample by selecting every 20th vehicle that passes (in any lane and going in any direction).

Step-by-step explanation:

8 0
2 years ago
A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T
Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

8 0
2 years ago
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