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Reil [10]
2 years ago
13

An empty can weighs 30 grams. The weight of the same can filled with liquid is 47.3 grams. Which equation could be used to find

w, the weight of the liquid?
Mathematics
1 answer:
Alika [10]2 years ago
3 0

Answer:

w = y - x is the equation to find w

Where,

w = Weight of the liquid

x = Weight of the empty can

y = Weight of the can with liquid

Step-by-step explanation:

Let

Weight of the empty can = x

Weight of the liquid = w

Weight of the can with liquid = x + w = y

x= 30 grams

w = ?

y= 47.3 grams

y = x + w

w = y - x

= 47.3 - 30

= 17.3

w= 17.3 grams

Therefore, the weight of the liquid is 17 .3 grams

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Answer:

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Step-by-step explanation:

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2 years ago
Which of the following are possible explicit formulas for the nth term of the constant velocity sequence below? Check all that a
oksano4ka [1.4K]
We have an arithmetic progression:
Nth=an
an=a₁+(n-1)d
a₁ is the first term.
n=number of terms.
d=common difference

10,17,24,31...
a₁=10
d=a₂-a₁=17-10=7

Therefore:
Nth=an
an=a₁+(n-1)d
an=10+(n-1)7
an=10+7n-7
an=7n+3.

Therefore: the formula for the nth is, an=a+(n-1), in this case; an=7n+3,

To check:
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a₂=7*2+3=17
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8 0
2 years ago
What are the real zeros of the function g(x) = x^3 + 2x^2 − x − 2?
PSYCHO15rus [73]
If there are real roots to be found for this polynomial, the Rational Root Theorem and synthetic division are the best way to find them. I teach from a book that uses c and d for the possible roots of the polynomial.  C is our constant, 2, and d is the leading coefficient, 1.  The factors of 2 are +/- 1 and +/-2.  The factors for 1 are +/-1 only.  Meaning, in all, there are 4 possibilities as roots for this polynomial.  But there are only 3 total (because our polynomial is a third degree), so we have to find the first one, at least, from our possibilities above.  Let's try x = -1, factor form (x + 1).  If there is no remainder when we do the synthetic division, then -1 is a root.  Put -1 outside the "box" and the coefficients from the polynomial inside: -1  (1  2  -1  -2).  Bring down the first coefficient of 1 and multiply it by the -1 outside to get -1.  Put that -1 up under the 2 and add to get 1.  Multiply 1 times the -1 to get -1 and put that -1 up under the -1 and add to get -2.  -1 times -2 is 2, and -2 + 2 = 0.  So we have our first root of (x+1).  The numbers we get when we do the addition along the way are the coefficients of our new polynomial, the depressed polynomial (NOT a sad one cuz it hates math, but a new polynomial that is one degree less than that of which we started!).  The new polynomial is x^{2} +x-2=0.  That can also be factored to find the remaining 2 roots.  Use standard factoring to find that the other 2 solutions are (x+2) and (x-1).  Our solutions then are x = -2, -1, 1, choice B from above.
6 0
2 years ago
Read 2 more answers
Ms. Hamby gave a quiz. Two students’ work and the answer key are shown. Ms. Hamby accepts equivalent answers in any form.
Luden [163]

Answer:

Student A and Student B both answered 2 questions correctly.

See explanation below

Step-by-step explanation:

Note: that answers in the form:

\frac{a}{-b}=\frac{-a}{b}=-\frac{a}{b}

ARE ALL EQUIVALENT.

First of all, 4/5 is equivalent to 0.8 if we do long division.

and 19/20 is 0.95 if we do long division.

Now, <u>Student A:</u>

Both of the fractions are correct and the negative sign is equivalent and makes the answer correct, so both are correct.

For <u>Student B:</u>

Similarly, both answers are correct for this student as well, looking at the equivalence we showed first.

Also, "-" (negative) in front of the parenthesis and inside parenthesis here doesn't matter.

Hence,

Student A and Student B both answered 2 questions correctly.

5 0
2 years ago
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