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2 years ago

OLYMPICS The number of men and women participating in the Winter

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

4 0

Answer:I can’t see the rest.

Step-by-step explanation:

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Olivia counted the number of ladybugs on each plant in her garden, then made the graph below.

Leni [432]

Answer:

A) Roses , C) Alfalfa

Step-by-step explanation:

Each ladybug symbol = 5 ladybugs

Roses: 35 ladybugs

Lettuce: 15 ladybugs

Alfalfa: 25 ladybugs

Grape vines: 10 ladybugs

10 ladybugs go from lettuce to alfalfa. You end up with:

Roses: 35 ladybugs

Lettuce: 5 ladybugs

Alfalfa: 35 ladybugs

Grape vines: 10 ladybugs

Roses and alfalfa end up with 35 ladybugs each.

Answer: A) Roses , C) Alfalfa

5 0

2 years ago

A pond had 60 fish. 27 were carp and the rest were tench. 10 fish were added. The probability that a fish picked at random is a

ivanzaharov [21]

Answer: 2

<u>Explanation:</u>

A pond had 60 fish but 10 were added so now the pond has 70 fish.

The probability of choosing a carp is 1/2 so $\frac{1}{2} (70)$ = 35 are now carp.

There were 27 carp and now there are 35 carp so 8 carp were added.

10 fish were added and 8 of them were carp so 2 of them were tench.

6 0

2 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

2 years ago

Brahmagupta solved a quadratic equation of the form ax2 + bx = c using the formula x =, which involved only one solution. Using

weeeeeb [17]

X2+7x-8=0
product=-8 times 1 = -8
sum= 7
{-1, 8}
x2-1x+8x-8=0
x(x-1)+8(x-1)=0
x+8=0 or X-1=0
x=-8

4 0

1 year ago

Read 2 more answers

Line segment pq shown on the graph below, is rotated 90 counterclockwise about point q to form pq

USPshnik [31]

Answer:

this isn’t a 100% guaranteed correct answer but maybe the second option saying “PQ and P’G’ are parallel”

(i’m doing the test rn)

4 0

2 years ago

Read 2 more answers