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2 years ago

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Business services ordered a chair that cost $220.59. Upon arrival they received an invoice for $261.47. If the California sales

tax rate is 7.9% what is the cost of shipping and handling

2 answers:

jonny [76]2 years ago

8 0

Answer:

The cost of shipping and handling is $23.45 .

Step-by-step explanation:

As given

Business services ordered a chair that cost $220.59.

if the California sales tax rate is 7.9%

7.9% is written in the decimal form

$= \frac{7.9}{100}$

= 0.079

Thus

Sales tax price = 0.079 × Cost of the chair

= 0.079 × $220.59

= $ 17.43 (Approx)

Thus

Cost of the ordered chair with sales tax price = Cost of the chair + Sales tax price .

= $ 220.59 + $17.43

= $ 238.02

As given

Upon arrival they received an invoice for $261.47.

Thus

Cost of shipping and handling = Cost mentioned in invoice - Cost of the ordered chair with sales tax price.

Put all the values in the above

Cost of shipping and handling = $261.47 - $238.02

= $ 23.45

Therefore the cost of shipping and handling is $23.45 .

sladkih [1.3K]2 years ago

6 0

Answer:

Cost of shipping and handling = $23.453

Step-by-step explanation:

Given

Price of Chair=$220.59

Tax=7.9%

Invoice Price=$261.47

In order to find the cost of shipping and handling, we have to subtract the cost of chair and the tax from the invoice price of chair.

To find the tax,

Tax amount=220.59*0.079

=$17.42661

Now,

Cost of shipping and handling=$261.47-$220.59-$17.42661

=$23.453 ..

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2 years ago

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2 years ago

There are 360 people in my school. 15 take calculus, physics, and chemistry, and 15 don't take any of them. 180 take calculus. T

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Answer:

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Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

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-The set B represents the students that take physics

-The set C represents the students that take chemistry.

-The set D represents the students that do not take any of them.

We have that:

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By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C), D$

There are 360 people in my school. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360$

The problem states that:

15 take calculus, physics, and chemistry, so:

$A \cap B \cap C = 15$

15 don't take any of them, so:

$D = 15$

75 take both calculus and chemistry, so:

$A \cap C = 75$

75 take both physics and chemistry, so:

$B \cap C = 75$

30 take both physics and calculus, so:

$A \cap B = 30$

Solution:

The problem states that 180 take calculus. So

$a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 180$

$a + 30 + 75 + 15 = 180$

$a = 180 - 120$

$a = 60$

Twice as many students take chemistry as take physics:

It means that: $C = 2B$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$B = b + 75 + 30 + 15$

$B = b + 120$

-------------------------------

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$C = c + 75 + 75 + 15$

$C = c + 165$

----------------------------------

Our interest is the number of student that take physics. We have to find B. For this we need to find b. We can write c as a function o b, and then replacing it in the equations that sums all the subsets.

$C = 2B$

$c + 165 = 2(b+120)$

$c = 2b + 240 - 165$

$c = 2b + 75$

The equation that sums all the subsets is:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360$

$60 + b + 2b + 75 + 30 + 75 + 15 + 15 = 360$

$3b + 270 = 360$

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$b = \frac{90}{3}$

$b = 30$

30 students take only physics.

The number of student that take physics is:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$B = b + 75 + 30 + 15$

$B = 30 + 120$

$B = 150$

150 students take physics.

6 0

2 years ago