Answer:
Step-by-step explanation:
Given that two well-known aviation training schools are being compared using random samples of their graduates
Fly more academy 70 of 140
Blue Yonder 104 of 260
Combined pass = (70+104) out of (140+260)
a) Pooled proportion=
b) H0: p1 = p2
Ha: p1 ≠p2
(two tailed test)
p difference= 
std error for difference (using pooled proportion) = 
Test statistic = p difff/std error = 4.034
c) Critical value for 0.05 is 1.96
d) p value is < 0.005
Since p < 0.05 our significant level we reject H0
There is significant difference between the two proportions.
Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15
From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,
0.048 is the probability that more than 950 message arrive in one minute.
After the 25% discount the vase would cost $18.00
Question:
Abdulla took a takie from his home to the air port. The taxi driver chared an initial fee of 12AED pluse 2.50AED per km. How much change should the taxi driver give mr abdulla bach if he gave him 100AED at the end of his trip
Answer:
88 - 2.50x
Step-by-step explanation:
Given :
Initial charge = 12
Charge per kilometer = 2.50
Amount given to driver = 100
Let distance from home to airport = x
Total charge = (initial charge + (distance * charge per km)
Total charge = 12 + 2.50x
Change = (Amount given to driver - total charge)
Change = (100 - (12 + 2.50x))
100 - 12 - 2.50x
88 - 2.50x
