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maw [93]
2 years ago
8

Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 7x2 + y2 and the

parabolic cylinder y = 3x2

Mathematics
1 answer:
Akimi4 [234]2 years ago
5 0
Letting x=t, we get y=3x^2=3t^2 and z=7x^2+y^2=7t^2+(3t^2)^2=7t^2+9t^4, so we can parameterize the intersection by

\mathbf r(t)=\langle t,3t^2,7t^2+9t^4\rangle

where -\infty.

Image attached.

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Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
2 years ago
Read 2 more answers
A certain forest covers an area of 4000 km2. Suppose that each year this area decreases by 7%. What will the area be after 5 yea
Levart [38]
Answer:

2,600

Explanation:

Your first step is to find 7% of 4000 ( this is what it is decreasing by per year).
As a result you end up with 280.
Multiply 280 by 5.
1,400 should be your answer( amount of km decreasing after 5 years). This is a decreasing forest, so you subtract 4,000by 1,400.
8 0
2 years ago
Which statement shows how two polynomials 5x − 6 and 6x + 2 demonstrate the closure property when multiplied?
Sunny_sXe [5.5K]
I dont see any statements. When you multiply the two you get: 30x^2 - 26x -12.
8 0
2 years ago
The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is (x
DaniilM [7]
We have the following equation:
 x2 + y2 + 42x + 38y - 47 = 0
 We rewrite the equation:
 x2 + 42x + y2 + 38y - 47 = 0
 x2 + 42x + y2 + 38y = 47
 Rewriting we have:
 x2 + 42x + (42/2) ^ 2 + y2 + 38y + (38/2) ^ 2 = 47 + (42/2) ^ 2 + (38/2) ^ 2
 x2 + 42x + 441 + y2 + 38y + 361 = 47 + 441 + 361
 Rewriting we have:
 (x + 21) ^ 2 + (y + 19) ^ 2 = 849
 The center of the circle is:
 (x, y) = (-21, -19)
 The radio is:
 r = root (849)
 r = (849) ^ 2

 A circle of the same radius is given by:
 x ^ 2 + y ^ 2 - 50x - 30y + 1 = 0
 Let's check:
 x ^ 2 - 50x + y ^ 2 - 30y + 1 = 0
 x ^ 2 - 50x + y ^ 2 - 30y = - 1
 x ^ 2 - 50x + (-50/2) ^ 2 + y ^ 2 - 30y + (-30/2) ^ 2 = - 1 + (-30/2) ^ 2 + (-50/2) ^ 2
 x ^ 2 - 50x + (-50/2) ^ 2 + y ^ 2 - 30y + (-30/2) ^ 2 = - 1 + 225 + 625
 (x-25) ^ 2 + (y-15) ^ 2 = 849
 Answer:
 
(x + 21) ^ 2 + (y + 19) ^ 2 = 849
 
(x, y) = (-21, -19)
 
r = (849) ^ 2
 
x ^ 2 + y ^ 2 - 50x - 30y + 1 = 0
5 0
2 years ago
Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve
kozerog [31]

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

4 0
2 years ago
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