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hram777 [196]
2 years ago
14

Determine the positive real root of ln(x²) = 0.7

Mathematics
1 answer:
timama [110]2 years ago
5 0

Answer:

i have no clue.

Step-by-step explanation:

i am very tired while doing a math link so please, don't give me any trouble with this :)

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Felicia wanted to find the number of boys in the school band if 30% of the 50 students are boys. Is her answer correct? Explain
docker41 [41]

Answer:

Creo que con 15

Step-by-step explanation:

50 -------> 100%

X ---------> 30%

X = (50*30)/100

X= 15 boys

4 0
1 year ago
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54 equals 9 more than a number t .
aleksandr82 [10.1K]

Answer:

t=45

Step-by-step explanation:

54=t+9

54-9=t

t=45

6 0
1 year ago
A textbook costs $65.49 before tax. The tax on the textbook is 6.5%. What is the total cost of the textbook? Round your answer t
AnnZ [28]
65.49*0.065 = 4.26
65.49+4.26 = $69.75
7 0
2 years ago
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What integer is equivalent to 25 3/2
antiseptic1488 [7]
<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
</span></span>
3 0
1 year ago
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AT&amp;T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let x be the number of additional line.

Cost of one additional line = $15

Cost of x additional line = \$15x

Total cost = Fixed cost + Addition cost

                = 125+15x

It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

8 0
2 years ago
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