I'll just show you how to make a frequency table using the above data.
We will group the data into class intervals and determine the frequency of the group.
<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17
Let us assign a class interval of 20.
Class Interval Tally Frequency
0-20 8, 12, 4, 18, 9, 5
21-40 25, 32, 39, 36, 33 5
41-60 45, 50, 67 3
61-80 62, 73, 80 3
81-100 99 1
That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
Person A buys 10 granola bars and 6 cups of yogurt for <em>$18</em>
Person B buys 5 granola bars and 4 cups of yogurt for <em>$9.50</em>
Let <u>x</u> represent the granola bars
Let <u>y</u> represent the yogurt
10x + 6y = 18 << ( Divide both sides by 2 )
The second equation is 5x + 4y = 9.50. Now subtract the two equations.
5x + 4y = 9.50
-5x - 3y = -9
y = $.50
5x + 3(.50) = 9
5x + 1.50 = 9
5x = 7.5
x = $1.50
I hope this answered your question
Please remember to rate my answer and comment bellow if you have any questions
So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.
So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>
Our result:
![\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Cbf%7B2a%5E2b%20%5Csqrt%5B4%5D%7B24a%5E2b%5E3%7D%20%7D%7D%7D)
We didn't just multiplied it, we also simplified it also.
The flight is in the shape of a parabola with a vertex 5 feet above the water and 1/2 * 33 = 16.5 feet horizontally from the point of leaving the water
y = a(x - h)^2 + k
where (h,k) is the vertex of the parabola and here it is (5 , 16.5), so we have the function:-
y = a(x - 16.5)^2 + 5
when x = 0 y = 0 so
0 = a(-16.5)^2 + 5
which gives a = -0.018365
So our function for the flight path is
y = -0.018365(x - 16.5)^2 + 5 Answer
