Answer: The minimum and maximum distances that Morgan's dog may be from the house are 508 meters and 492 meters.
Step-by-step explanation:
Hi, to answer this question we have to solve the given equation: |x – 500| = 8.
The modulus can take a positive value (x - 500) or a negative value (-x+500).
- <em>For the positive value:
</em>
x -500 = 8
x = 8+500
x =508
- <em>For the negative value:
</em>
- (x -500) =8
-x +500 =8
500 -8 = x
492 =x
So, the minimum and maximum distances that Morgan's dog may be from the house are 508 meters and 492 meters.
Feel free to ask for more if needed or if you did not understand something.
Answer:
The first part is C) The increase in loudness per centimeter is the same for both
The second part is A) Thor's
Step-by-step explanation:
First part:
<u>Whose loudness increases more per additional centimeter of height?</u>
C) The increase in loudness per centimeter is the same for both
Second part:
<u>Whose strike is louder when he strikes from a height of 40 centimeters?</u>
A) Thor's
I did it on Khan and it was correct.
Answer:
212m
Step-by-step explanation:
The set up will be equivalent to a right angled triangle where the height is the opposite side facing the 45° angle directly. The length of the rope will be the slant side which is the hypotenuse.
Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;
Since we have the angle theta = 45° and opposite = 150m
According to SOH;
Sin theta = opposite/hypotenuse.
Sin45° = 150/hyp
hyp = 150/sin45°
hyp = 150/(1/√2)
hyp = 150×√2
hyp = 150√2 m
hyp = 212.13m
Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m
